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Leto [7]
3 years ago
9

Write the equation of a line with a slope of -1 passing through the point (0,5)

Mathematics
1 answer:
elixir [45]3 years ago
8 0
The\ slope-intercept\ form\ of\ the\ line:y=mx+b\\\\m-the\ slope\\b-y-intercept\\\\m=-1;\ (0;\ 5)\to b=5\\\\Answer:\boxed{y=-x+5}
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The function f(x)= -6x+11 has a range given by {-37,-25,-13,-1}.Select the domain values of the function from the list 1,2,3,4,5
andreev551 [17]
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.

So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.

f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
4 0
3 years ago
What is the answer to...<br> 70 - 6 × (4 - 1)2
elixir [45]

Answer:

34

Step-by-step explanation:

5 0
3 years ago
Order the angle measures , , and from least to greatest.
Neko [114]

Mark the theorem below

  • The angle which measures biggest the opposite side of that angle is biggest.

Here

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  • JH<IH<JI

Now

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4 0
2 years ago
Read 2 more answers
Find the solutions to the equation below. Check all that apply.
lubasha [3.4K]

2x^2 + 9x + 4 = 0

x^2 + 9/2*x + 2 = 0

x = - 9/4 +- √(81/16 - 32/16) = - 9/4 +- 7/4

x1 = - 1/2

x2 = - 4

5 0
3 years ago
Read 2 more answers
The area of the base (B) of a triangular pyramid is 28 cm. The perimeter (p) is 20 cm, and the slant height (S) is 5 cm. Determi
kenny6666 [7]

Answer:

The pyramid's surface area is 78 square centimeters

Step-by-step explanation:

The formula of the surface area of a pyramid is S.A = A + \frac{1}{2} p s, where

  • A is the area of its base
  • p is the perimeter of its base
  • s is the slant height of it

∵ The area of the base of a triangular pyramid is 28 cm²

∴ A = 28 cm²

∵ The perimeter of the base is 20 cm

∴ p = 20 cm

∵ The he slant height is 5 cm

∴ s = 5 cm

- Substitute these values in the formula of the surface area

   above to find it

∵ S.A = 28 + \frac{1}{2} (20)(5)

∴ S.A = 28 + 50

∴ S.A = 78 cm²

The pyramid's surface area is 78 square centimeters

5 0
3 years ago
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