D(-1,-1), E(-8,-4), F(-8,-8)
We are given with the sequence -20, -16, -12, -8. From this sequence, we can see that the arithmetic difference is +4, from -(-20 + 16). hence following the arithmetic formula of an = a1 + d *(n-1). Substituting, an = -20 + 4 *(n-1) where n is an integer
Answer:
-2, 3/7, 1/2, 1.2
Step-by-step explanation:
Increasing == least to greatest in value.
-2 = -2
3/7 = 0.429
1/2 = 0.5
1.2 = 1.2
Answer:
x = 15
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ KLM is an external angle of the triangle, thus
∠ KLM = ∠ JKL + ∠ KJL , substitute values
5x - 7 = x + 20 + 2x + 3
5x - 7 = 3x + 23 ( subtract 3x from both sides )
2x - 7 = 23 ( add 7 to both sides )
2x = 30 ( divide both sides by 2 )
x = 15
Answer:
option b)
tan²θ + 1 = sec²θ
Step-by-step explanation:
The Pythagorean trigonometric identity is a trigonometric identity expressing the Pythagorean theorem in terms of trigonometric functions.
hypotenuse² = height² + base²
Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.
<h3>1)</h3>
sin²θ + 1 = cos²θ incorrect
<h3>sin²θ + cos²θ = 1 correct</h3><h3 /><h3>2)</h3>
by dividing first identity by cos²θ
sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ
<h3>tan²θ + 1 = sec²θ correct</h3><h3 /><h3>3)</h3>
1 - cot²θ = cosec²θ incorrect
by dividing first identity by sin²θ
sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ
<h3>1 + cot²θ = cosec²θ correct</h3><h3 /><h3>4)</h3>
1 - cos²θ = tan²θ
not such pythagorus identity exists
