Answer:
A
Step-by-step explanation:
Hopefully this helps!
Answer:
The velocity of jet in still air is
and velocity of wind is
.
Step-by-step explanation:
Let x be the rate of the jet in still air and y be the rate of the wind.
Given:
Velocity against wind, a jet travels 2160 miles in 3 hours.
Velocity against wind ![=\frac{2160}{3} = 720 miles/hour](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2160%7D%7B3%7D%20%3D%20720%20miles%2Fhour)
Flying with the wind, same jet travels 6000 miles in 6 hours.
Flying with the wind ![=\frac{6000}{6} = 1000 miles/hour](https://tex.z-dn.net/?f=%3D%5Cfrac%7B6000%7D%7B6%7D%20%3D%201000%20miles%2Fhour)
As such its velocity against wind is ![x-y](https://tex.z-dn.net/?f=x-y)
and with wind is
therefore
------------(1)
---------------(2)
Adding equation 1 and 2.
![2x=1720](https://tex.z-dn.net/?f=2x%3D1720)
![x=\frac{1720}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1720%7D%7B2%7D)
![x=860](https://tex.z-dn.net/?f=x%3D860)
Put x value in equation 2
![860+y=1000](https://tex.z-dn.net/?f=860%2By%3D1000)
![y=1000-860](https://tex.z-dn.net/?f=y%3D1000-860)
![y=140](https://tex.z-dn.net/?f=y%3D140)
Hence velocity of jet in still air is
and velocity of wind is
.
Step-by-step explanation:
In the recursive formula an = an−1 + 5
![a_n = a_{n-1}+5](https://tex.z-dn.net/?f=a_n%20%3D%20a_%7Bn-1%7D%2B5)
Suppose if a_5 is the nth term then previous term is a_4
To get the previous term we need to subtract 1 from the n
So a_n is the nth term
is the previous term
Here 5 represents the common difference between two terms
So value of previous term is represented by
![a_{n-1}](https://tex.z-dn.net/?f=a_%7Bn-1%7D)
Answer : ![a_{n-1}](https://tex.z-dn.net/?f=a_%7Bn-1%7D)
It’s on like the side if I was home I would show my hw has the same answer/problem simple