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Igoryamba
3 years ago
10

Which of the following equations have infinitely many solutions?

Mathematics
1 answer:
Elis [28]3 years ago
8 0
It is the third one, -10x-10=-10x-10
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FOR WHICH POLYGON ARE BOTH x= -1 and y= -2 lines of symmetry? ILL BRAINLIEST YOU IF YOU GET IT RIGHT HELP ME PLZ
snow_lady [41]

Answer:

C

Step-by-step explanation:

The line of symmetry is a line that splits the figure into 2 halves where each half is a mirror image of the other. In the third figure, if a line is drawn through x = -1, the halves mirror each other. If a line is drawn through y = -2, the top and bottom halves mirror each other.

3 0
2 years ago
5. Let A = (x, y), B = {1,2). Find the Cartesian products of A and B: A x B? (Hint: the result will be a set of pairs (a, b) whe
hichkok12 [17]

Answer: A x B = {(x,1), (x,2), (y,1), (y,2)}

Step-by-step explanation:

The Cartesian product of any two sets M and N is the set of all possible ordered pairs such that the elements of M are first values and the elements of N are the second values.

The Cartesian product of sets M and N is denoted by M × N.

For Example : M = {x,y} and N={a,b}

Then , M × N ={(x,a), (x,b), (y,a), (y,b)}

Given : Let A = {x, y}, B = {1,2}

Then , the Cartesian products of A and B will be :

A x B = {(x,1), (x,2), (y,1), (y,2)}

Hence, the Cartesian products of A and B = A x B = {(x,1), (x,2), (y,1), (y,2)}

8 0
3 years ago
Eric jogged 31/4 miles on monday 5 5/8 miles on tuesday and 8 miles on wensday .suppose he continues the pattern for the remaind
Troyanec [42]
The is increasing by 2 3/8
So the answer is 12 3/4 miles on Friday

Hope this helps :)
3 0
3 years ago
I just need help :))
rosijanka [135]
U will take the two diagrams
And name them A N B
U then solve the triangle by triangle
6 0
2 years ago
Read 2 more answers
Solve the system by elimination. (Please explain how to do it)
Naddika [18.5K]

Apply to Row 2 : Row 2 + Row 1

2x + 2y + 3z = 0

y + 4z = -3

2x + 3y + 3z = 5

Apply to Row 3: Row 3 - Row 1

2x + 2y + 3z = 0

y + 4z = -3

y = 5

Apply to Row 3: Row 3 - Row 2

2x + 2y + 3z = 0

y + 4z = -3

-4z = 8

Simplify rows

2x + 2y + 3z = 0

y + 4z = -3

z = -2

<em>Note that the matrix is in echelon form now. The next steps are for back substitution.</em>

Apply to Row 2: Row 2 - 4 Row 3

2x + 2y + 3z = 0

y = 5

z = -2

Apply to Row 1: Row 1 - 3 Row 3

2x + 2y = 6

y = 5

z = -2

Apply to Row 1: Row 1 - 2 Row 2

2x = -4

y = 5

z = 2

Simplify the rows

<u>x = -2</u>

<u>y = 5</u>

<u>z = -2</u>

3 0
3 years ago
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