1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mihalych1998 [28]
2 years ago
5

Please need answers 7 please need now

Mathematics
1 answer:
podryga [215]2 years ago
3 0

Answer:

-15

Step-by-step explanation:

as i said if the signs are different the result is negative

You might be interested in
Write an equation in point-slope form for each line.<br> (If possible please show work)
Free_Kalibri [48]

Answer:

so

slope is calculated this way:

\frac{3 - 6}{2 - 1}  =  \frac{ - 3}{1}  =  - 3

let's calculate y init by:

3 = -3×2 + b

b = 9

so equation is:

y=-3x+9

6 0
3 years ago
If ⅙ of a roll of wallpaper covers ¼ of the wall. How many rolls of paper are needed to cover 4 walls?
AVprozaik [17]

Answer:

if 1/6 of a roll of paper covers 1/4 of a wall, this means that we will need 4/6 of a roll to cover a whole wall, now the question is asking how many rolls will we need to cover 4 walls, we already know that it takes 4/6 to fill one wall so if we add 4/6+4/6+4/6+4/6 we will get 16/6 or 2 4/6

we will need 16/6 or 2 4/6 of rolls of paper to cover 4 walls

5 0
2 years ago
Solve each equation (quadratic pattern)
dusya [7]

Answer:  x = 2

<u>Step-by-step explanation:</u>

2^{2x}-2^x-12=0\\\\\text{Let u = }2^x\\\\u^2-u-12=0\\(u-4)(u+3)=0\\\\u-4=0\quad and\quad u+3=0\\u=4\qquad and\quad u=-3\\\\\text{Substitute u with }2^x\\2^x=4\qquad and \quad 2^x=-3\\2^x=2^2\quad and\quad \text{not possible}\\\boxed{x=2}

********************************************************************************

Answer:  x = 0

<u>Step-by-step explanation:</u>

3^{2x}+3^{x+1}-4=0\\\\3^{2x}+3^x\cdot3^1-4=0\\\\\text{Let u = }3^x\\u^2+3u-4=0\\\\(u+4)(u-1)=0\\\\u+4=0\quad and\quad u-1=0\\u=-4\qquad and\quad u=1\\\\\text{Substitute u with }3^x\\3^x=-4\qquad and\quad 3^x=1\\\text{not possible}\ and\quad 3^x=3^0\\.\qquad \qquad \qquad \qquad \boxed{x=0}

********************************************************************************

Answer:  No Solution

<u>Step-by-step explanation:</u>

4^x+6\cdot 2^x+8=0\\\\2\cdot 2^x+6\cdot 2^x+8=0\\\\\text{Let u = }2^x\\2u+6u+8=0\\8u+8=0\\8u=-8\\u=-1\\\\\text{Substitute u with }2^x\\2^x=-1\\\text{not possible}

********************************************************************************

Answer:  No Solution

<u>Step-by-step explanation:</u>

<u>9^x=3^x-6\\\\3\cdot 3^x=1\cdot 3^x-6\\\\\text{Let u = }3^x\\\\3u=u-6\\2u=-6\\u=-3\\\\\text{Substitute u with }3^x\\3^x=-3\\\text{not possible}</u>

<u />

6 0
2 years ago
Can someone help me plz
natali 33 [55]

Answer:

Step-by-step explanation:

correct equation is n - 31 = 52

3 0
3 years ago
Convert 17/20 into percentages .
PilotLPTM [1.2K]

Answer:

85%

Step-by-step explanation:

85% because I searched and it gave me 85%

6 0
2 years ago
Read 2 more answers
Other questions:
  • Can anyone help with number 54?
    14·1 answer
  • When talking about place value every three numbers is a______________
    9·1 answer
  • Is it possible for an exponential equation to have no solutions? If so, give an example. If not, explain why.
    10·1 answer
  • PLEASE HELP ME
    15·1 answer
  • 67.82 miles per hour to feet per second
    6·1 answer
  • A local bowling alley charges $4.50 to play one game and $4 to rent one pair of shoes. The expression 4.5g + 4 represents the to
    5·1 answer
  • In binary system 100 + 101 = 1001. write decimal equivalent of the summand and sum.
    14·2 answers
  • A triangle has side lengths measuring 20 cm, 5 cm, and n cm. Which describes the possible values of n?
    6·2 answers
  • You drop a feather from a height of 160 centimeters. The function h= -16x^2 + 160 represents the height H (in centimeters) of th
    14·1 answer
  • 1/2 (89-18) = -57<br> g=
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!