Answer:
-1
Step-by-step explanation:
Assuming that you're talking about a standard deck of 52 cards, there are 4 tens and 4 aces.
So, at the beginning, you have probability 4/52=1/13 to draw a ten.
You replace, and you have an identical probability to draw an ace (you still have 4 favourable cases over 52 total cases).
Multiply the two probabilities to find the answer:

X% of 4 = x*4/100 = 0.04x
y% of 5 = x*5/100 = 0.05y
x% of 4 + y% of 5 = 0.04x + 0.05y
How you express a number, n, as percentage of 11?: [n/11]*100= 9.10n %
Then make n = 0.04x + 0.05y
9.10n %= 9.10[0.04x + 0.05y] %= (0.3656x + 0.455y)%
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The area, in square inches, outside the smaller region, but inside the larger region is 99π
<h3>How to determine the area, in square inches, outside the smaller region, but inside the larger region?</h3>
The given parameters are:
Radius, r1 = 1 inch
Radius, r2 = 10 inches
The area, in square inches, outside the smaller region, but inside the larger region is calculated as
Area = π(R^2 - r^2)
This gives
Area = π(10^2 - 1^2)
Evaluate the difference
Area = 99π
Hence, the area, in square inches, outside the smaller region, but inside the larger region is 99π
Read more about area at:
brainly.com/question/17335144
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6x + 7 = 8x - 17
6x- 8x = -17 - 7
-2x = -24 • divide both sides by -2
Thefore x = 12