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3 years ago

The greatest common factor of 30, 48, and 60 is?

Mathematics

2 answers:

Marizza181 [45]3 years ago

8 0

Answer:

Step-by-step explanation:

Because 6x5 is 30 and 6x8 is 48 and 6x10 is 60

Natali5045456 [20]3 years ago

5 0

Answer:

Step-by-step explanation:

6 goes in 30 5 times.

into 48 six times.

into 60 ten times.

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Simplify the expression(a4−6a2b2+ b4)−(−2a4+5a2b2+ 3b4) and hence, find its value for a = 2and b = −1.

ELEN [110]

Answer:

(a) $3a^4 - 11a^2b^2 -2b^4$

(b) $3a^4 - 11a^2b^2 -2b^4= 2$

Step-by-step explanation:

Given

$(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)$

Solving (a): Simplify

$(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)$

Open brackets

$a^4 - 6a^2b^2+ b^4 +2a^4-5a^2b^2- 3b^4$

Collect Like Terms

$a^4 +2a^4- 6a^2b^2-5a^2b^2+ b^4 - 3b^4$

Simplify Like Terms

$3a^4 - 11a^2b^2 -2b^4$

Solving (b): Simplify when a = 2 and b = -1

$3a^4 - 11a^2b^2 -2b^4$

$3*(2)^4 - 11*(2^2)*(-1)^2 -2*(-1)^4$

$3 * 16 - 11 * 4 * 1 - 2 * 1$

$48 - 44 - 2$

$= 2$

Hence:

$3a^4 - 11a^2b^2 -2b^4= 2$

4 0

3 years ago

A total of 40 people made cakes for a bake sale. Each person made 3 cakes. Ms. Sanchez

Elena L [17]

18 chocolate cakes were made. 40(3)= 120 cakes in total. 15%=.15 .15(120)= 18

7 0

4 years ago

Please help me asap

satela [25.4K]

I think it’s the second one sorry if I’m wrong ahhh

4 0

3 years ago

50 Points

ANEK [815]

Answer:

x=5

Step-by-step explanation:

First you have to solve for y. Since it is a isoceles triangle, the two base angles are equal. You dont even need to solve for y because both of them will equal 73. Now you know two of the angles are 73 degrees, 146 in total. Since you know the total degrees in a triangle is 180, set up an equation that is adding all the angles to equal 180. Then solve for x.

Solve:

73+73+(6x+4)=180

146+6x+4=180

150+6x=180

6x=30

x=5

5 0

3 years ago

Read 2 more answers

ΔABC is a right triangle in which angle B is a right angle, AB = 1, AC = 2, and BC = square root of 3 . cos C × sin A equals wha

ad-work [718]

Remark

Study the triangle carefully. It may not be exactly as you have drawn it, but it will work if you just follow the givens.

Givens

AC = 2

AB = 1

BC = sqrt(3)

Step One

Find Cos C

Cos(C) = adjacent / Hypotenuse

Cos(C) = BC / AB

Cos(C) = sqrt(3)/2

Step Two

Find Sin(A)

Sin(A) = opposite / hypotenuse

Sin(A) = AB / AC

Sin(A) = 1/2

Step Three

Find Cos(C) * Sin(A)

Cos(C) * Sin(A) = sqrt(3)/2 * 1/2 = sqrt(3) / 4 <<<< Answer

4 0

3 years ago