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fgiga [73]
3 years ago
15

Calculate the value of x​

Mathematics
2 answers:
Otrada [13]3 years ago
5 0

Answer:

21

Step-by-step explanation:

liq [111]3 years ago
5 0
X = 7
6(7) = 42 + 12 = 54
This is your answer
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Solve for L <br> 10LW=V<br><br> i need help answering this question
vlabodo [156]
10LW=V

L/10W= V/10W

L= V/10W
3 0
3 years ago
Pythagoras question plz help
motikmotik
From the two right triangles, you can write the following equations using the Pythagorean theorem. Let's call that shared leg in the middle "y"

y^2 + b^2 = a^2
y^2 + c^2 = x^2


y^2 + b^2 = a^2
re-write this to get "y" alone for substitution.
y^2 = a^2 - b^2
substitute (a^2 - b^2) for y^2 in the other equation. y^2 + c^2 = x^2

a^2 - b^2 + c^2 = x^2

Now put in the values given for a,b,c to solve for x

(7.1)^2 - (5.6)^2 + (5.7)^2 = x^2
51.54 = x^2
square root
7.2 = x


6 0
3 years ago
Please someone what is the total surface area of this pryamid ​
Dimas [21]

Answer:

\large\boxed{C.\ (25+25\sqrt3)\ in^2}

Step-by-step explanation:

We have the square and four equilateral triangles.

The formula of an area of a squre:

A_S=a^2

a - length of side

The formula of an area of an equilateral triangle:

A_T=\dfrac{a^2\sqrt3}{4}

a - length of side

Clculate the areas:

SQURE:

A_S=x^2\ in^2

TRIANGLE:

A_T=\dfrac{x^2\sqrt3}{4}\ in^2

The SURFACE AREA of a square pyramid:

S.A.=A_S+4A_T\\\\S.A.=x^2+4\cdot\dfrac{x^2\sqrt3}{4}=x^2+x^2\sqrt3

Put x = 5:

S.A.=5^2+5^2\sqrt3=(25+25\sqrt3)\ in^2

7 0
3 years ago
Please help! I will give Brainliest!<br> Who is correct?
katrin [286]
Irving is correct! A triangle is unique if the two shorter segments is "less than or equal to" the third segment.
4.5+8.5=13 which is less than 14.

note: Could you do me a favor and mark me as brainiest, that would really help motivate me to help out more people in the future. Thanks! ☺️ <3
5 0
3 years ago
PLEASE HELP AND ANSWER!!!!! Which of the following reveals the minimum value for the equation 2x2 + 12x − 14 = 0?
NARA [144]

Answer:

The correct option is 3.

Step-by-step explanation:

The given equation is

2x^2+12x-14=0

It can be written as

(2x^2+12x)-14=0

Taking out the common factor form the parenthesis.

2(x^2+6x)-14=0

If an expression is defined as x^2+bx then we add (\frac{b}{2})^2 to make it perfect square.

In the above equation b=6.

Add and subtract 3^2 in the parenthesis.

2(x^2+6x+3^2-3^2)-14=0

2(x^2+6x+3^2)-2(3^2)-14=0

2(x+3)^2-18-14=0

2(x+3)^2-32=0             .... (1)

Add 32 on both sides.

2(x+3)^2=32

The vertex from of a parabola is

p(x)=a(x-h)^2+k        .... (2)

If a>0, then k is minimum value at x=h.

From (1) and (2) in is clear that a=2, h=-3 and k=-32. It means the minimum value is -32 at x=-3.

The equation 2(x+3)^2=32 reveals the minimum value for the given equation.

Therefore the correct option is 3.

5 0
3 years ago
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