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3 years ago

What two numbers add to -14 and multiply to -45

Mathematics

1 answer:

aliya0001 [1]3 years ago

3 0

-9 and -5
add -9 and -5 you get -14 and if you multiply
-9x-5=-45

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- 3m - 6 = 6 - 7m pls help!

Alja [10]

Answer:

m = 3

Step-by-step explanation:

-3m - 6 = 6 - 7m

-3m + 7m = 6 + 6

4m = 12

m = 12/4

m = 3

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3 years ago

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Which expression is a cube root of -1+i√3?

Tpy6a [65]

Answer:

<em>The correct option is C.</em>

Step-by-step explanation:

<u>Root Of Complex Numbers</u>

If a complex number is expressed in polar form as

$Z=(r,\theta)$

Then the cubic roots of Z are

$\displaystyle Z_1=\left(\sqrt[3]{r},\frac{\theta}{3}\right)$

$\displaystyle Z_2=\left(\sqrt[3]{r},\frac{\theta}{3}+120^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{r},\frac{\theta}{3}+240^o\right)$

We are given the complex number in rectangular components

$Z=-1+i\sqrt{3}$

Converting to polar form

$r=\sqrt{(-1)^2+(\sqrt{3})^2}=2$

$\displaystyle tan\theta=\frac{\sqrt{3}}{-1}=-\sqrt{3}$

It's located in the second quadrant, so

$\theta=120^o$

The number if polar form is

$Z=(2,120^o)$

Its cubic roots are

$\displaystyle Z_1=\left(\sqrt[3]{2},\frac{120^o}{3}\right)=\left(\sqrt[3]{2},40^o\right)$

$\displaystyle Z_2=\left(\sqrt[3]{2},40^o+120^o\right)=\left(\sqrt[3]{2},160^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{2},40^o+240^o\right)=\left(\sqrt[3]{2},280^o\right)$

Converting the first solution to rectangular coordinates

$z_1=\sqrt[3]{2}(\ cos40^o+i\ sin40^o)$

The correct option is C.

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4 years ago

Simplify the expression -2(6-5g)

boyakko [2]

Answer:

10g-12

Step-by-step explanation:

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3 years ago

I need help ASAP plss!!

topjm [15]

Answer:

c. 8.359

Step-by-step explanation:

i hope this helps :)

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3 years ago

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PLEASE HELP

Sergeeva-Olga [200]

Answer:

Use these points.

(1, -2.5)

(-1, -5.5)

3/2x1=1.5-4=-2.5

3/2x-1=-1.5-4=-5.5

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3 years ago

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