Answer:
Step-by-step explanation:
Given
See attachment for triangles
Solving (a)
The tan of an angle is:
From the given triangle.
So, we have:
Solving (b)
The cos of an angle is:
From the given triangle.
So, we have:
28 as a prime factorization
1 answer:
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Answer:
Step-by-step explanation:
1. a). Hypotenuse² = (Leg 1)² + (Leg 2)²
h² = 10² + 24²
h = √676
h = 26
(b). Hypotenuse² = (Leg 1)² + (Leg 2)²
(25)² = (15)² + (leg 2)²
Leg 2 = √(625 - 225)
= √400
= 20
(c). Hypotenuse² = (Leg 1)² + (Leg 2)²
h² = 4² + 6²
h = √(16 + 36)
h = √52
h = 2√13
(d). Hypotenuse² = (Leg 1)² + (Leg 2)²
(14)² = (Leg 1)² + 7²
Leg 1 = √(196 - 49)
= √147
= 7√3
2). Hypotenuse² = (Leg 1)² + (Leg 2)²
Leg 1 = leg 2 = 7 units [Since, triangle is an isosceles triangle]
h² = 7² + 7²
h = √98
h = 7√2
Option (1) is the correct option.
3). Hypotenuse² = (Leg 1)² + (Leg 2)²
(26)² = (Leg 1)² + (10)²
Leg 1 = √(676 - 100) = 24
Area of a right triangle =
=
= 120 square units
Option (3) is the correct option.