Y=4x because 20/5 equals 4
Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
The common difference, d, is 5 and the starting value, a, is 2.
Filling this in the form of
<span>you get
</span>
Answer:
10.67
Step-by-step explanation:
The 10 stays as it is. The 2/3 is approximated by 0.67 (to the nearest hundredth). Thus, we have 10.67 to the nearest hundredth.
Answer:
the standard form of equation is in the form of
x - 9y = -45 , so the answer is B
