Ask question

Ask question

All categories

3 years ago

15

Where my math wizzes at? I really need help and fast. A dialation has a center (0, 0, 0). Find the image of the point (-1, 2, 0)

for the scale factor of 3? There are no answer choices.

1 answer:

defon3 years ago

7 0

Multiply every coordinate by the scale factor 3

(-1,2,0) ----> (-3,6,0) is the answer

You might be interested in

A vender sold a combined total of 131 sodas and hot dogs. The number of hot dogs sold was 31 less than the number of sodas sold.

puteri [66]

Answer:

81 sodas and 50 hotdogs

Step-by-step explanation:

131 = x + x - 31

131 <em>+</em><em> </em><em>3</em><em>1</em><em> </em>= x + x - 31 <em>+</em><em> </em><em>3</em><em>1</em>

162 = x + x

x = 81

131 = 81 + (81 - 31)

131 = 81 sodas + 50 hot dogs

5 0

3 years ago

Find X. Show work. There is a photo of the problem. Thank you very much :)

mezya [45]

Answer:

x = 2.24

Step-by-step explanation:

I will ASSUME that the 15 represents the angle in degrees

We can make a similar triangle by adding the purple lines as shown.

Any triangle inscribed in a circle with one side as a diameter is a right triangle.

We know it is similar triangle because it shares two common angles, the right angle and the 75° angle at the far right. Then

z = 2Rsin15 = 2(16.7)sin15

x = zsin15 = 2(16.7)sin²15 = 2.237375756799...

5 0

3 years ago

A ray of light with intensity lo falls vertically on the sur face of the sea and at ten meters deep its intensity is 10/3. Assum

seropon [69]

Answer:

intensity = $\frac{Io}{15}$

intensity = $\frac{Io}{30}$

depth = 333.33 m

Step-by-step explanation:

given data

deep = 10 m

intensity = Io

intensity = Io/3

to find out

intensity of light at 50 m and 100 m and 1/100 of initial intensity remain ?

solution

we know here that intensity is inversely proportional to deep so

intensity = k × $\frac{1}{Deep}$ .................1

here k is constant

so we have given 10 m deep so

$\frac{Io}{3}$ = $\frac{k}{10}$

so k = Io × $\frac{10}{3}$ ................2

so from equation 1 when 100 m deep and 50 m deep

intensity = k × $\frac{1}{Deep}$

intensity = Io × $\frac{10}{3}$ × $\frac{1}{50}$

intensity = $\frac{Io}{15}$

and

intensity = Io × $\frac{10}{3}$ × $\frac{1}{100}$

intensity = $\frac{Io}{30}$

and

at intensity Io/100

intensity = k × $\frac{1}{Deep}$

$\frac{Io}{100}$ = Io × $\frac{10}{3}$ × $\frac{1}{D}$

D = 333.33 m

so depth = 333.33 m

3 0

3 years ago

If 3a +5b =10 and 5a +3b =30 what is the average of a and b?

saw5 [17]

Hello, please consider the following.

$3a+5b + 5a + 3b = 8(a+b)=10+30=40\\\\a+b=\dfrac{40}{8}=5$

And the average is

$\dfrac{a+b}{2}\boxed{=\dfrac{5}{2}}$

Thank you.

6 0

3 years ago

Redondear a 100,000 el numero 5,370,288

Softa [21]

Para redondear este número a 1,000, verifiquemos el tercer dígito del número.

Si el dígito es mayor que 5, aumentamos el siguiente número en 1 unidad.

Si el dígito es menor o igual a 5, mantenemos el siguiente número.

El tercer dígito es 3, por lo que el número redondeado es:

$25,000$

6 0

1 year ago