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Slav-nsk [51]
3 years ago
8

What is 1.9541 rounded to the nearest thousandth

Mathematics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

1.954

so 4 is in the thousandths

Step-by-step explanation:

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Find the sum which amounts to Rs 9261 at 10% per annum compound interest for 18 months ,interest payable half yearly
AleksAgata [21]

Find the sum which amounts to Rs 9261 at 10% per annum compound interest for 18 months ,interest payable half yearly

A=P(1+\frac{r}{n})^{nt} , where A is amount , r is rate =10% = 0.10 , n is intervals of compounding n=2 , t is time = 18 months=1.5 years

Lets plug in

9261=P(1+\frac{0.10}{2})^{2*1.5}

9261 = P(1.002)^{3}

9261 = P(1.006012008)

divide both sides by 1.006012008

P= Rs 9205.6555

6 0
3 years ago
Use the compound interest formula to compute the total amount accumulated and the interest earned.
mezya [45]
A=3,500×(1+0.011÷12)^(12×4)
A=3,657.36

Interest earned
=3657.36-3500=157.36
6 0
3 years ago
How many lines can be constructed perpendicular to AC that pass through point D?
Vladimir [108]

Answer:

1

Step-by-step explanation:

This is the answer by definition.

5 0
1 year ago
First anserw gets brainest 8th grade, root squared question
Katen [24]

Answer:

±11

11*11=121

-11*-11=121

4 0
3 years ago
A survey showed that 77% of us need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. 13 adults are randomly
earnstyle [38]

Using the binomial distribution, it is found that the probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

For each person, there are only two possible outcomes, either they need correction for their eyesight, or they do not. The probability of a person needing correction is independent of any other person, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • A survey showed that 77% of us need correction, hence p = 0.77.
  • 13 adults are randomly selected, hence n = 13.

The probability that at least 12 of them need correction for their eyesight is given by:

P(X \geq 12) = P(X = 12) + P(X = 13)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 12) = C_{13,12}.(0.77)^{12}.(0.23)^{1} = 0.1299

P(X = 13) = C_{13,13}.(0.77)^{13}.(0.23)^{0} = 0.0334

Then:

P(X \geq 12) = P(X = 12) + P(X = 13) = 0.1299 + 0.0334 = 0.163

The probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

More can be learned about the binomial distribution at brainly.com/question/24863377

7 0
2 years ago
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