3 years ago

3.2g of sugar is needed to make 8 cakes. How much sugar is needed for 12 cakes?

Mathematics

2 answers:

4vir4ik [10]3 years ago

8 0

3.2s:8c

4.8s:12c

Therefore, you would need 4.8g of sugar to make 12 cakes. This was solved by using ratios.

umka2103 [35]3 years ago

3 0

4.8 grams of sugar is for 12 cakes

You might be interested in

Which statement is true

AlladinOne [14]

3) an $8 delivery fee and $1.50 per litre of water

This is because the $8 is a constant baseline, then adding $1.50 times the amount of litres purchased.

8 0

3 years ago

what is the density of a sheet of aluminum that has a volume of 328.4 cubic centimeters and a mass of 780 grams

Nata [24]

Answer:

$\large\boxed{density=\dfrac{1950}{821}\ \dfrac{g}{cm^3}\approx2.375\ \dfrac{g}{cm^3}}$

Step-by-step explanation:

$density=\dfrac{mass}{volume}\\\\\text{We have}\\\\mass=780\ g\\volume=328.4\ cm^3\\\\\text{Substitute:}\\\\density=\dfrac{780g}{328.4\ cm^3}=\dfrac{780\cdot10}{328.4\cdot10}\ \dfrac{g}{cm^3}=\dfrac{7800}{3284}\ \dfrac{g}{cm^3}=\dfrac{7800:4}{3284:4}\ \dfrac{g}{cm^3}\\\\=\dfrac{1950}{821}\ \dfrac{g}{cm^3}$

3 0

3 years ago

Write 760% as a decimal and as a simplified fraction

SVETLANKA909090 [29]

7.6

760/100

76/10

7 6/10

8 0

3 years ago

Find the cube roots of 8(cos 216° + i sin 216°).

Tomtit [17]

$z^3=8(\cos216^\circ+i\sin216^\circ)$
$z^3=2^3(\cos(6^3)^\circ+i\sin(6^3)^\circ)$
$\implies z=8^{1/3}\left(\cos\left(\dfrac{216+360k}3\right)^\circ+i\sin\left(\dfrac{216+360k}3\right)^\circ\right)$

where $k=0,1,2$ . So the third roots are

$z=\begin{cases}2(\cos72^\circ+i\sin72^\circ)\\2(\cos192^\circ+i\sin192^\circ)\\2(\cos312^\circ+i\sin312^\circ)\end{cases}$

5 0

3 years ago

When multiplying two negative numbers, what kind of number does one always get for an answer?

kvasek [131]

When we multiply two negative numbers, one always gets a positive number.

(-)×(-)= +

Hope it helps

4 0

3 years ago

Read 2 more answers