Answer:
-8
Step-by-step explanation:
The equation has no solution
Answer:
(98/100)*110 = $107.8
Step-by-step explanation:
The amount of substance left of a radioactive element of half life,

after a time, t, is given by:

Given that <span>potassium-40 has a half life of approximately 1.25 billion
years.
The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

Therefore, </span><span>the maximum age of a fossil that we could date using 40k is
12.5 billion years.</span>
Answer:
13.3 (rounded in the tenth place)
Step-by-step explanation:
equation: a^2 + b^2 = c^2
What we know :
a = 20^2 = 400
b = what we are looking for
c = 24^2 = 576
Our equation will be looking like :
20^2 + b^2 = 24^2
400 + b^2 = 576
Now we subtract 400 into 576
which equals 176 now we square root it
and get 13.2664 but we gotta square root it and that will lead you to have 13.3 as your answer