Photos and videos have become an important part of the online social experience, with more than half of Internet users posting p
hotos or videos online that they have taken themselves. Let A be the event an Internet user posts photos that they have taken themselves, and B be the event an Internet user posts videos that they have taken themselves. A research center finds that P(A) = 0.44, P(B) = 0.26, and P(A or B) = 0.50.
Required:
Make a Venn diagram showing the events {A and B}, {A and not B}, {B and not A}, and {neither A nor B}.
Required:
Make a Venn diagram showing the events {A and B}, {A and not B}, {B and not A}, and {neither A nor B}.
1 answer:
Answer:
{A and B} = 0.20
{A and not B} = 0.24
{B and not A} = 0.06
{neither A nor B} = 0.50
Step-by-step explanation:
Given the following :
P(A) = 0.44
P(B) = 0.26
P(A or B) = 0.50.
{A and B} = 0.20
{A and not B} = 0.24
{B and not A} = 0.06
{neither A nor B} = 0.50
Kindly check attached picture for detailed explanation
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4.75x +3.50
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11.504.75x
Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag of fruit, you round down. So your final answer would be 2 bags of fruit.
Then to solve, first subtract 3.50 from both sides to get:
11.50
Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag of fruit, you round down. So your final answer would be 2 bags of fruit.
For each given region , the average value of
over
is the integral of
over
divided by the area of
. In both cases,
is a rectangle so the area is trivial.
a. The area of is
. The integral of
over
is
So the average value of over this region is 0.
b. The area of is
. The integral of
is
The average vale of over this region is then
.
Answer:
89%
Step-by-step explanation:
If he's on time on the previous day, there's a 10% probability he'll be late, which means there's a 90% probability that he'll be on time.
If he's late on the previous day, there's a 20% probability he'll be late, which means there's a 80% probability that he'll be on time.
He's on time on Monday, so there's a 10% probability he'll be late on Tuesday and a 90% probability he'll be on time.
If he's on time on Tuesday, there's a 10% probability he'll be late on Wednesday and a 90% probability he'll be on time.
If he's late on Tuesday, there's a 20% probability he'll be late on Wednesday and a 80% probability he'll be on time.
So the probability he'll be on time on Wednesday is:
0.10 (0.80) + 0.90 (0.90) = 0.89
