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MAXImum [283]
3 years ago
10

Unit cubes and solid figures

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0
The dimensions are 10 x 10 x 10. I this is because when it was it can hold up to 1000 cubes, that says the volume is 1000. I know that V=lwh so 1000 = lwh. If you do 10 x 10 x 10 you get 100! Hope this helped :D

Please mark me the brainiest!
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Can a triangle be formed with 4cm 8cm and 12cm
worty [1.4K]
No. 4^2 + 8^2 or 16 + 64 is 80, and the hypotenuse, 12 (144) is not 80.
7 0
3 years ago
For each point identify the axis or quadrant where the point is located…
My name is Ann [436]

Answer:

quadrant ll

Step-by-step explanation:

A point on the y-axis will always have an x-coordinate of zero. Instructions: In the figure above, the point with coordinates (4,2) is located in quadrant I. The point with coordinates (-3,4) is located in quadrant II.

6 0
3 years ago
Help me please!! i am already failing the test
Ivan

Answer:

2x²+2x

Step-by-step explanation:

you have f(x)= x+1 and g(x)= 2x

you must multiply the 2 polynomials

(1x·2x) +( 1·2x)

1·2=2  x^1·x^1=x²

2x²

1·2x=2x

4 0
3 years ago
Which of the following best classifies a quadrilateral with coordinates A(2,6), B(5, 1), C(10, 4), and D(7,9)?
navik [9.2K]

Answer:

a rhombus

Step-by-step explanation:

If you graph the problem, you can see the shape of the quadrilateral. I attached a picture of a graph below. I hope this helped you!! Have a great rest of your day.

3 0
3 years ago
Find the 63rd term of the arithmetic sequence -1, 5, 11, ...−1,5,11,...
Ugo [173]

Answer:

a_6_3=371

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference

we have

-1,5,11,...

Let

a_1=-1\\a_2=5\\a_3=11

a_2-a_1=5-(-1)=5+1=6

a_3-a_2=11-5=6

The common difference is d=6

We can write an Arithmetic Sequence as a rule

a_n=a_1+d(n-1)

where

a_n is the nth term                

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have

n=63\\d=6\\a_1=-1

substitute

a_6_3=-1+6(63-1)

a_6_3=-1+6(62)

a_6_3=-1+372

a_6_3=371

6 0
3 years ago
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