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77julia77 [94]
3 years ago
13

PLz help with these questions. For questions 1 and 2 , write each expression using a single exponent. 1)   x^9/x^2 2) h^14/h^5 F

or questions 3 and 4, simplify each expression. 3) 4^4/4^6 4) 5^0 For questions 6-8, multiply the following polynomial. 6) -2r( 8r + 5 ) 7) 4a( a^2 + 7a + 4 ) 8) ( 2y - 3 )( 3y - 2 )
Mathematics
1 answer:
Zepler [3.9K]3 years ago
4 0
For questions 1 and 2 , write each expression using a single exponent.

1) \ x^9:x^2=x^7\\
\\
2) \ h^{14}:h^{5}=h^9

<span>For questions 3 and 4, simplify each expression.
</span>
3) \ 4^4:4^6=4^{-2}=\frac{1}{4^2}=\frac{1}{16}\\&#10;\\&#10;4) \ 5^0=1

<span>For questions 6-8, multiply the following polynomial.
</span>
6) \ -2r(8r+5)=-16r^2-10r\\&#10;\\&#10;7) \ 4a(a^2+7a+4)=4a^3+28a^2+16a\\&#10;\\&#10;8) \ (2y-3)(3y-2)=6y^2-4y-9y+6=6y^2-13y+6




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kap26 [50]
Rewriting the question, the given lengths that were cut from the board were 30 3/4 inches, 12 1/4 inches, and 16 1/4 inches. To obtain the remaining length of the board, all of the measurements cut are to be added and subtracted from 72 inches. This is shown below:

30 3/4 + 12 1/4 + 16 1/4 = 237/4 = 59.25 inches.

Remaining length of board = 72 - 59.25 = 12.75 inches.

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Solve problems <br>5 1/2×3 1/3​
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Anarime estimates that of people booked on the fights actually show up in the e books 70 people on a fight for which the maximum
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Answer:

An airline estimates that 94% of people booked on their flights actually show up. If the airline books 77 people on the flight for which the maximum number is 75, what is the probability that the number of people who show up will exceed the capacity of the plane?

-------------------------

Binomial Problem with n = 77 and p = 0.94

---

P(76 <= x <= 77) = 1-P(0 <=x <= 75) = 1 - binomcdf(77,0.94,75) = 0.0504

==================

Cheers,

Stan H.

3 0
3 years ago
I can't figure this out
andriy [413]
Suppose that equation of parabola is
y =ax² + bx + c


Since parabola passes through the point (2,−15) then 
−15 = 4a + 2b + c

Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c

Since parabola passes through the point (−3,−5), then 
−5 = 9a − 3b + c


Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = −5

Solving it we get that 
a = −2, b = −4, c = 1

Thus, equation of parabola is
y = −2x²− 4x + 1

____________________

Rewriting in the form of 
(x - h)² = 4p(y - k)

i) -2x² - 4x + 1 = y

ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)

iii) -3x² - 7x - 49/36 = y - 1 - 49/36
(Adding -49/36 to both sides to get perfect square on LHS)

iv) -3(x² + 7/3x + 49/36) = y - 3
(Taking out -3 common from LHS)

v) -3(x + 7/6)² = y - 445/36 

vi) (x + 7/6)² = -⅓(y - 445/36) 
(Shifting -⅓ to RHS)

vii) (x + 1)² = 4(-1/12)(y - 445/36)
(Rewriting in the form of 4(-1/12) ; This is 4p) 


So, after rewriting the equation would be - 

(x + 7/6)² = 4(-⅛)(y - 445/36)

__________________

I hope this is what you wanted.

Regards,
Divyanka♪
__________________
6 0
3 years ago
Read 2 more answers
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