Step 1. Simplify 9^2 to 81
81 <span>÷ (-3)^0
Step 2. Use Rule of Zero: x^0 = 1
81 </span><span>÷ 1
Step 3. Simplify
81</span>
Answer:
yes
Step-by-step explanation:
i cant see da pic
Answer:
1.) 1-b, 2-a, 3-d, 4-c
Step-by-step explanation:
You recognize that the point-slope form of the equation for a line with slope m and point (h, k) is ...
... y - k = m(x - h)
____
Match this form to the given equations to determine (h, k). Once you determine (h, k) from the equation, find that point in the list of points to get your match-up. (All the slopes are correct, so you don't need to do any more work than just described.)
_____
For problems 3.) and 4.), use the above form with the given point and slope.
Answer:
x > 9
Step-by-step explanation:
2x - 7 > 11
2x > 18
x > 9
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
