Answer:
a) 20<h≤30.
b) 26.17 hrs
Step-by-step explanation:
The missing table is shown in attachment.
Part a)
We need to find the class interval that contains the median.
The total frequency is

The median class corresponds to half

That is the 15th value.
We start adding the frequency from the top obtain the least cumulative frequency greater or equal to 15.
2+8+9=19
This corresponds to the class interval 20<h≤30.
Adding from the bottom also gives the same result.
Therefore the median class is 20<h≤30.
b) Since this is a grouped data we use the midpoint to represent the class.
The median is given by :




The answer is A.
The way you know this is by graphing the first function.
The second function is in a different format, so you just have to isolate Y.
-1/3x + y = -1
y= 1/3x -1 OR y= -1 + 1/3x
both of the functions have the same slope, but different y-intercepts. therefore, they'll never touch. making them infinite solutions.
it's also A because both of the slopes are positive, the slopes in graph D are negative.
So, the answer is A.
Hope this helps! xx
The answer to ur question is 1.77309723E28.
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Answer:
yes
Step-by-step explanation: