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3 years ago

Please help me! Do any one of them, as long as the answer is correct!

Mathematics

1 answer:

quester [9]3 years ago

6 0

Answer:

1.) 1-b, 2-a, 3-d, 4-c

Step-by-step explanation:

You recognize that the point-slope form of the equation for a line with slope m and point (h, k) is ...

... y - k = m(x - h)

____

Match this form to the given equations to determine (h, k). Once you determine (h, k) from the equation, find that point in the list of points to get your match-up. (All the slopes are correct, so you don't need to do any more work than just described.)

_____

For problems 3.) and 4.), use the above form with the given point and slope.

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Please help ASAP !!!!!

zloy xaker [14]

Answer:

i need points im really sorry

Step-by-step explanation:

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3 years ago

In your office 1/8 of 288 employees work part-time how many are part-time

bearhunter [10]

That would be 1/8 times 288, so the answer would be 36 part time workers.

5 0

3 years ago

Plz help me with this

Setler79 [48]

Answer: x = 8

(the correct answer was not provided as an option)

<u>Step-by-step explanation:</u>

$log_2(x-6)+log_2(x-4)=log_2(x)\\\\log_2[(x-6)(x-4)]=log_2(x)\\\\(x-6)(x-4)=x\\\\x^2-10x+24=x\\\\x^2-11x+24=0\\\\(x-3)(x-8)=0\\\\x=3\qquad x=8\\\\\\\text{The term after the log symbol (inside the parenthesis) must be greater than 0!}\\\\Check:\\3-6>0\ \text{FALSE --- so 3 is not a valid solution}\\\\8-6>0\ \text{TRUE}\\8-4>0\ \text{TRUE}\\8>0\ \text{TRUE --- 8 is a valid solution because it is true for all}$

8 0

3 years ago

If BK = 15, what is KQ?

svlad2 [7]

Answer:

KQ = bk/2kq

Kq = 25/2 = 12.5

Step-by-step explanation:

Hope this helps!

8 0

2 years ago

Find the solution(s) to 2x2 + 5x – 3 = 0.

iren2701 [21]

Answer:

C and E

Step-by-step explanation:

Let's factor this the "old fashioned" way. The standard form of a quadratic is

$y=ax^2+bx+c$

If you're familiar with the quadratic formula I'd say throw it into that, but if not, again, let's do it the "old fashioned" way.

We need to find the product of our a and c. Our a = 2 and our c = -3. So that gives us a -6. Now we have to find the factors of 6 (the negative right now doesn't matter so much). The factors of 6 are 1, 6 and 2, 3. Both of those possibilities will work to give us a +5, which is the linear term. Puttng in the 2, 3 first:

$0=2x^2+3x+2x-3$

Now group the terms together into groups of 2:

$0=(2x^2+3x)+(2x-3)$

The idea is to factor out something common in each term so that what's left over in the parenthesis in both terms is exactly the same. In the first term we can factor out a common x, and in the second term, the only thing common is a 1. So that looks like this:

$x(2x+3)+1(2x-3)$

What's inside those parenthesis are not actually identical, so 2 and 3 won't work. Lets try 1 and 6. For those 2 numbers to equal a +5, the 6 is positive and the 1 is negative. So let's try that:

$(2x^2+6x)+(-x-3)$

In the first term we can factor out the common 2x and in the second term we can factor out the common -1:

2x(x + 3) - 1(x + 3)

Now what's common is (x + 3), so we can factor THAT out and what is left over is 2x - 1:

(x + 3)(2x - 1) = 0

If x + 3 = 0, then x = -3

and if 2x - 1 = 0, then 2x = 1 and x = 1/2

5 0

3 years ago