Step-by-step explanation:
Given equations:
y = x² + 3x - 29 ------ (i)
y = 2x - 9 ---------------- (ii)
Now to solve this problem, we must determine the value of x and y;
Equate equations 1 and 2;
x² + 3x - 29 = 2x - 9
x² + 3x - 2x - 29 + 9 = 0
x² + x - 20 = 0
x² + 5x - 4x - 20 = 0
x(x + 5 ) - 4(x + 5) = 0
(x - 4) (x+ 5) = 0
x - 4 = 0 or x + 5 = 0
x = 4 or x = -5;
So; solve for y now;
y = 2x - 9
input x = 4 or x = -5;
y = 2(4) - 9 or y = 2(-5) - 9
y = -1 or y = -19
Answer:
12
Step-by-step explanation:
Answer:
(8 . x)
Step-by-step explanation:
8 times the product of drag
Answer:
Which measure?
Step-by-step explanation:
9514 1404 393
Answer:
-13/11
Step-by-step explanation:
Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...
![\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto%201%7D%5Cdfrac%7Bn%7D%7Bd%7D%3D%5Cdfrac%7Bn%27%7D%7Bd%27%7D%3D%5Cleft.%5Cdfrac%7B%5Cdfrac%7B4%7D%7B3%5Csqrt%5B3%5D%7B4x-3%7D%7D-%5Cdfrac%7B7%7D%7B2%5Csqrt%7B7x-6%7D%7D%7D%7B%5Cdfrac%7B5%7D%7B2%5Csqrt%7B5x-4%7D%7D-%5Cdfrac%7B2%7D%7B3%5Csqrt%5B3%5D%7B2x-1%7D%7D%7D%5Cright%7C_%7Bx%3D1%7D%3D%5Cdfrac%7B4%2F3-7%2F2%7D%7B5%2F2-2%2F3%7D%3D%5Cdfrac%7B8-21%7D%7B15-4%7D%5C%5C%5C%5C%3D%5Cboxed%7B-%5Cdfrac%7B13%7D%7B11%7D%7D)
