The first problem is true because with multiplication it doesn't matter which order it is in.
The second problem is false because you will get a different quotient depending on which numbers are on which side of the equation.
Answer:
x = (-5 ± 2√10) / 3
Step-by-step explanation:
5 − 10x − 3x² = 0
Write in standard form:
-3x² − 10x + 5 = 0
Solve with quadratic formula:
x = [ -b ± √(b² − 4ac) ] / 2a
x = [ -(-10) ± √((-10)² − 4(-3)(5)) ] / 2(-3)
x = [ 10 ± √(100 + 60) ] / -6
x = (10 ± 4√10) / -6
x = (-5 ± 2√10) / 3
Answer:
0.3
Step-by-step explanation:
Find the number in the tenth place
3
and look one place to the right for the rounding digit
1
. Round up if this number is greater than or equal to
5
and round down if it is less than
5
.
0.3
Answer:
7y+5z+10
Step-by-step explanation:
7y+5z+10
In order to solve this problem, we must solve an equation.
First, we need to define our unknown.
Let's call our number "n".
So, the sum of the number and 6 is the same as saying n+6
Then we need to multiply it by 2 (since it's twice the sum)
2(n+6)
This whole thing is equal to three times of the difference of the number and 8
n-8 is equal to the difference between the number and 8, then we need to multiply it by three.
3(n-8)
now, we set both sides equal and solve
The number is 36
