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3 years ago

Select Equal or Not Equal to correctly classify each statement.

Mathematics

2 answers:

baherus [9]3 years ago

6 0

Answer:

me lmo

Step-by-step explanation:

Black_prince [1.1K]3 years ago

3 0

The first problem is true because with multiplication it doesn't matter which order it is in.

The second problem is false because you will get a different quotient depending on which numbers are on which side of the equation.

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Plzz help this is due today

andreyandreev [35.5K]

Answer:

Major Arc

Step-by-step explanation:

because it's bigger then half of the circle

8 0

2 years ago

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Given the drawing as shown below and that p || a, which of the following cannot be supported by the evidence shown?

masya89 [10]

Answer:

D. <b ≅ <g

Step-by-step explanation:

Given that lines p and q are parallel to each other, therefore the following can be concluded:

✔️<f ≅ <h, this is because they are both Vertical angles.

✔️<d and <h are supplematry, this is because they are same side consecutive interior angles. Consecutive angles are supplematry.

✔️<a and <b are supplematry, this is because they are linear pair angles.

✔️<b cannot be congruent to <g. They are not corresponding angles, nor are they alternate interior angles.

4 0

2 years ago

Help with the question above please????

sukhopar [10]

Don’t even know sry bout that

7 0

2 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

1 year ago

In March, April, and June it rained 2 inches. In February, May, and September it rained 1 inch. In August and October, it rained

koban [17]

Answer:

Step-by-step explanation:

Hope this Helps :D

4 0

3 years ago

Read 2 more answers