All categories

3 years ago

Select Equal or Not Equal to correctly classify each statement.

Mathematics

2 answers:

baherus [9]3 years ago

6 0

Answer:

me lmo

Step-by-step explanation:

Black_prince [1.1K]3 years ago

3 0

The first problem is true because with multiplication it doesn't matter which order it is in.

The second problem is false because you will get a different quotient depending on which numbers are on which side of the equation.

You might be interested in

Which pair of angles are supplmentary?

olga55 [171]

Answer:

1+2, 1+4, 2+1, 2+3, 3+2, 3+4, 4+1, 4+3, 5+6, 5+8, 6+5, 6+7, 7+8, 7+6, 8+5, 8+7

Step-by-step explanation:

To be supplementary is to be equal to 180 degrees.

3 0

3 years ago

Read 2 more answers

Which congruence theorem can be used to prove △ABC ≅ △DEF? AAS ASA HL SAS

Delicious77 [7]

Answer:

Step-by-step explanation:

Use the HL Congruence Theorem to prove that the triangles are congruent.

8 0

3 years ago

A school has a hurdle track that is 1/5 of a mile long. They are considering extending the track to be 1/4 of a mile long. The c

Anastaziya [24]

Answer: 4/5

Step-by-step explanation:

Here, The hurdle track that is 1/5 of a mile long.

And, After extending the track, the length of the hurdle track = 1/4 of a mile

Therefore, the unit rate of length in the longer track per mile of length in the shorter track = the initial length of the hurdle track / the final length of the hurdel track

= $\frac{1/5}{1/4}$

= $\frac{4}{5}$

3 0

3 years ago

Read 2 more answers

(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions

Sliva [168]

$\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}$
$\frac{1(x+2)}{(x-1)(x+2)}+ \frac{2(x-1)}{(x+2)(x-1)}= \frac{3(x-1)(x+2)}{2}$
$\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}$
$\frac{x+2+2x-1}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}$
$\frac{3x+1}{(x-1)(x+2)}= \frac{3(x^2+x-2)}{2}$
$\frac{}{(x-1)(x+2)}= \frac{3x^2+3x-6)}{2}$
$\frac{3x+1}{(x^2+x-2)}= \frac{3x^2+3x-6)}{2}$
$\frac{2(3x+1)}{2(x^2+x-2)}= \frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}$
$\frac{2(3x+1)}{2(x^2+x-2)}-\frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}=0$
$\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0$

this will be continued

5 0

4 years ago

PLEASE ANSWER QUICKLY AS POSSIBLE WILL GIVE BRAINLYEST TO FIRST CORRECT

Tems11 [23]

Answer:

Soln:

Step-by-step explanation:

Here,

Base(b) =9

Opposite/Perpendicular (p)= x

Hypotenus (h) = 24

We know,

(p)^2 = (h)^2 - (b)^2

(x)^2 = (24)^2 - (9)^2

x^2 = 576 - 81

x^2 = 495

x = root under 495

6 0

2 years ago

Read 2 more answers