<h2>
Change of the distance between the observer and the airplane when X = 5 miles is 348.84 mph</h2>
Step-by-step explanation:
We have by Pythagoras theorem
Distance between the observer and the airplane² = Horizontal distance² + Altitude²
d² = h² + a²
Here we have
h = X = 5 miles
a = 7 miles
d² = 5² + 7² = 74
d =8.60 miles

Differentiating d² = h² + a² with respect to time

Change of the distance between the observer and the airplane when X = 5 miles is 348.84 mph
Answer:
$253
Step-by-step explanation:
Margin of error is the critical value times the standard error.
MoE = z × σ/√n
At 99% confidence, z = 2.576.
MoE = 2.576 × 844/√74
MoE = 253
Answer:
C.60
Step-by-step explanation:
Just multiply 300 by 9 and then divide by 45.
Answer:
The missing value is 512
![8=\sqrt[3]{512}](https://tex.z-dn.net/?f=8%3D%5Csqrt%5B3%5D%7B512%7D)
Step-by-step explanation:
Let
x ----> the missing value
we have
![8=\sqrt[3]{x}](https://tex.z-dn.net/?f=8%3D%5Csqrt%5B3%5D%7Bx%7D)
solve for x
That means-----> isolate the variable x
Elevated both sides to the cube
![8^{3}=(\sqrt[3]{x})^{3}](https://tex.z-dn.net/?f=8%5E%7B3%7D%3D%28%5Csqrt%5B3%5D%7Bx%7D%29%5E%7B3%7D)
Remember that
![(\sqrt[3]{a})^{3}=(a^{\frac{1}{3}})^3=a](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Ba%7D%29%5E%7B3%7D%3D%28a%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3Da)
so
![(\sqrt[3]{x})^{3}=x](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bx%7D%29%5E%7B3%7D%3Dx)
substitute


Rewrite

so
the equation is
![8=\sqrt[3]{512}](https://tex.z-dn.net/?f=8%3D%5Csqrt%5B3%5D%7B512%7D)