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Vsevolod [243]
3 years ago
13

The president of a company wants to know about how many of the office chairs in the building need to be replaced. Which sampling

method will result in a sample that is not biased?
She puts notices in the break rooms asking employees to e-mail her about the condition of their chairs.

She inspects every chair in the sales department.

She gives a list of employee names to the maintenance supervisor and tells him to inspect the chair of every fifth employee.

She asks every other employee she sees in the cafeteria about his chair.
Mathematics
1 answer:
alukav5142 [94]3 years ago
3 0
<span>B) She inspects every chair in the sales department.
</span>
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Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
2 years ago
Find the surface area of a cylinder with diameter of 10 and height of 4
castortr0y [4]

Answer:

282.74

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
(1/2)^2 - 6 (2 - 2/3)<br><br> Note: 1/2 and 2/3 is a fraction
shusha [124]
\bf \left( \cfrac{1}{2} \right)^2-6\left(2-\cfrac{2}{3}  \right)\impliedby recall~~\mathbb{PEMDAS}&#10;\\\\\\&#10;\cfrac{1^2}{2^2}-6\left( \cfrac{6-2}{3} \right)\implies \cfrac{1}{4}-6\left(  \cfrac{4}{3}\right)\implies \cfrac{1}{4}-\cfrac{6\cdot 4}{3}\implies \cfrac{1}{4}-\cfrac{24}{3}&#10;\\\\\\&#10;\cfrac{1}{4}-8\impliedby LCD~~4\implies \cfrac{1-32}{4}\implies \cfrac{-31}{4}\implies -7\frac{3}{4}
5 0
3 years ago
The endpoints of GH are G(10,1) and H(3,5). What is the midpoint of GH?
svet-max [94.6K]

Answer:

The answer is (6.5,3)

Step-by-step explanation:

The solution is in the image

8 0
1 year ago
PLEASE HELP !!!!!!!! WILL MARK BRAINLIEST IF CAN!
Margaret [11]

Answer:

The answer is A. You just have to plug in.

Step-by-step explanation:

5x - y/3= 13

(2,-9) and (3,-6)

5(2) - -9/3 = 13

10 + 3 = 13

13 = 13 (true)

5(3) - -6/3= 13

15+ 2 = 13

17 = 13 (wrong)


8 0
2 years ago
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