Answer: 
Step-by-step explanation:





B = {a, b, c, d}
C = {0, a, 2, b}
B ∪ C = {a, b, c, d, 0, 2}
<h3>Answer: E)</h3>
Everything from the set B and everything from the set C give to one set. Duplicated elements are written only once.
<span>17 1/3 + (-50 1/3) -5 1/2
= -33 - 5 1/2
= (</span>-33 ) + ( - 5 1/2)
<span>= -38 1/2
</span>
P(<100) = P((new or change) & <100) = P(new & <100) + P(change & <100)
... = P(<100 | new)*P(new) + P(<100 | change)*P(change)
... = 0.90*0.70 + 0.20*0.30
... = 0.63 + 0.06 = 0.69 . . . . probability of completing a transaction in < 100 ms
The answer to the expression is -97/20 or -4.85