All categories

3 years ago

1. Look for a pattern in the first three equations. Then, fill in the missing numbers in the rest of the

Mathematics

1 answer:

Alla [95]3 years ago

4 0

Answer:

1=1 times 2/2 1 + 2=2 times 3/2 1 +2+3=3 times 4/2 1+2+3+4=4 times 5/2 1+2+3+4+5=5 times 6/2

You might be interested in

A customer goes to a bank and gets change for a $100 bill. The change is to be in $1, $5, and $10 bills. There were four times a

alexira [117]

Answer:

Step-by-step explanation:

x = number of $1 bills

y = number of $5 bills

z = number of $10 bills

We know that:

x + y + z = 25 (total amount of bills)

x + 5y + 10z = 100 (total amount of money)

y = 4z (Given)

Substitute the third equation into the first one.

x + 4z + z = 25

x = 25 - 5z

Put this into the second equation.

(25 - 5z) + 5 (4z) + 10z = 100

Simplify and solve.

25 - 5z + 20z + 10z = 100

25z + 25 = 100

25z = 75

z = 3

Substitute this into y = 4z

y = 4 * 3

y = 12

So, there are 12 $5 bills.

5 0

2 years ago

Read 2 more answers

The unit rate of 15 degrees in 2 hours

Neporo4naja [7]

Solution: 7.5 Degrees per hour

Reasoning: 15/2 is equal to 7 1/2 or 7.5

5 0

2 years ago

Read 2 more answers

Need Help!!! Answer Plzz

vampirchik [111]

A. the first one will give you a perpendicular line to BA

7 0

3 years ago

HELP ASAP PLEASE I HAVE TO TURN THIS IN SOON

Rom4ik [11]

Answer:

Step-by-step explanation:

It has a slope of -1/4

and it's y intercept is 2

y = -1/4x + 2

7 0

2 years ago

An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est

MrRa [10]

Answer:

85% level of the confidence interval is

(26.337, 26.662)

Step-by-step explanation:

Explanation:-

Given the size of the sample 'n' = 295

Mean of the sample x⁻ = 26.5

The Standard deviation of the Population = 2.7

85% level of the confidence interval is determined by

$(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })$

Critical value Z₀.₁₅ = 1.036

85% level of the confidence interval is determined by

$(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })$

$(26.9 -1.036 \frac{2.7}{\sqrt{295} } , 26.5 + 1.036 \frac{2.7}{\sqrt{295} })$

( 26.5 - 0.1628 , 26.5+0.1628)

(26.3372,26.6628)

7 0

3 years ago