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2 years ago

Please help asap 20 pts

Mathematics

1 answer:

ValentinkaMS [17]2 years ago

6 0

Look for the graph where the line crosses the y axis at y=-1, and whose slope is -3. The answer is b.

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James thinks the perimeter of this figure is 6x + 10. Ana thinks it is 6x + 6. Who is

BlackZzzverrR [31]

whats the figure? I need the background knowledge

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2 years ago

How do you solve an equation with Fractions?<br><br> Ex. 1/2(7x + 48)<br> Ex. -(1/2 x -3)+4(x + 5)

Assoli18 [71]

Its best to turn fractions into decimals so its easier to solve the problem, in order to do this you would divide the number on the top to the number on the bottom. Ex: 1 divide by 2 So the numerator divided by the denominator. The top of the faction is the numerator and the bottom of the faction is the denominator. So 1 divided by 2 = 0.5 you would replace 0.5 for the 1/2.

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3 years ago

Please help me on 7&8 and please show your work :)

Llana [10]

7. 6/12 or 1/2 | 8. 5/12

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3 years ago

Sa = 2(pi)(r)(h) + 2(pi)(r^2) v = (pi)(r^2)(h) find the surface area and the volume.

LenKa [72]

If Sa=2πrh+2π $r^{2}$ v=π $r^{2}h$ then the surface area is π $r^{2} h$ and volume is

(rh-2h)/2r.

Given Sa=2πrh+2π $r^{2} v$ =π $r^{2}h$ .

We have to find surface area and volume from the given expression.

Volume is basically amount of substance a container can hold in its capacity.

First we will find the value of v from the expression. Because they are in equal to each other, we can easily find the value of v.

2πrh+2π $r^{2}$ v=π $r^{2}$ h

Keeping the term containing v at left side and take all other to right side.

2π $r^{2}$ v=π $r^{2}h$ -2πrh

v=(π $r^{2}$ h-2πrh)/2π $r^{2}$

v=π $r^{2} h$ /2π $r^{2}$ -2πrh/2π $r^{2}$

v=h/2-h/r

v=h(r-2)/2r

Put the value of v in Sa=2πrh+2π $r^{2} v$

Sa=2πrh+2π $r^{2}$ *h(r-2)/2r

=2πrh+2πrh(r-2)/2

=2πrh+πrh(r-2)

=2πrh+π $r^{2}$ h-2πrh

=π $r^{2}$ h

Hence surface area is π $r^{2}$ h and volume is h(r-2)/2.

Learn more about surface area at brainly.com/question/16519513

#SPJ4

6 0

2 years ago

Evaluate the expression. (-3)^-2

Wewaii [24]

$~~(-3)^{-2}\\\\\\=\dfrac 1{(-3)^2}~~~~~~~~~~~~~~~~~~~~~~~~~;\left[k^{-n} = \dfrac 1{k^n},~~~ k \neq 0\right]\\\\\\=\dfrac 1{(-1)^2 \cdot 3^2}\\\\\\=\dfrac 1{1 \times 9}\\\\\\=\dfrac 19$

3 0

1 year ago

Read 2 more answers