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3 years ago

Hi can anybody help me please i will mark them as a brainlest

Mathematics

2 answers:

Ket [755]3 years ago

8 0

Answer:

C has the largest area.

Step-by-step explanation:

3x3=9, 9/2=4.5

Ede4ka [16]3 years ago

4 0

Answer:

area 4.5

Step-by-step explanation:

C has the largest Area. It's area is 4.5

hope this helps

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PLEASE HELP!!!!!!!!<br> also, show all work<br> Thank you:)

barxatty [35]

Problem 1

<h3>Answer: 104 cubic inches</h3>

----------------------

Explanation:

The prisms are similar so they have the same shape, but different sizes.

The linear scale factor from small to large is:

large/small = 10/4 = 2.5

Meaning that we multiply each dimension of the smaller prism by 2.5 to get the corresponding side length of the larger prism

4*2.5 = 10

This linear scale factor is then cubed to get the volume scale factor

(2.5)^3 = 15.625

Which tells us:

larger volume = 15.625*(smaller volume)

smaller volume = (larger volume)/15.625

smaller volume = (1625)/15.625

smaller volume = 104 cubic inches

========================================================

Problem 2

<h3>Answer: 650 square inches</h3>

----------------------

Explanation:

We will go back to the linear scale factor of 2.5

This time, we square it to get (2.5)^2 = 6.25

This is the surface area scale factor.

larger surface area = 6.25*(smaller surface area)

larger surface area = 6.25*(104)

larger surface area = 650 square inches

4 0

2 years ago

Will give brainliest! which scatterplot could have a trend line whose equation is y = -x + 8?

insens350 [35]

Answer:

Step-by-step explanation:

because you started at 8 and the dots are going down

5 0

3 years ago

The Insurance Institute reports that the mean amount of life insurance per household in the US is $110,000. This follows a norma

nata0808 [166]

Answer:

a) $\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85$

b) Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

c) $P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)$

And we can use the complement rule and we got:

$P(Z>0.354) = 1-P(Z$

d) $P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)$

And we can use the complement rule and we got:

$P(Z>-1.768) = 1-P(Z$

e) $P(100000< \bar X$

And we can use the complement rule and we got:

$P(-1.768$

Step-by-step explanation:

a. If we select a random sample of 50 households, what is the standard error of the mean?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the amount of life insurance of a population, and for this case we know the distribution for X is given by:

$X \sim N(110000,40000)$

Where $\mu=110000$ and $\sigma=40000$

If we select a sample size of n =35 the standard error is given by:

$\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85$

b. What is the expected shape of the distribution of the sample mean?

Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

c. What is the likelihood of selecting a sample with a mean of at least $112,000?

For this case we want this probability:

$P(X > 112000)$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)$

And we can use the complement rule and we got:

$P(Z>0.354) = 1-P(Z$

d. What is the likelihood of selecting a sample with a mean of more than $100,000?

For this case we want this probability:

$P(X > 100000)$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)$

And we can use the complement rule and we got:

$P(Z>-1.768) = 1-P(Z$

e. Find the likelihood of selecting a sample with a mean of more than $100,000 but less than $112,000

For this case we want this probability:

$P(100000$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P(100000< \bar X$

And we can use the complement rule and we got:

$P(-1.768$

8 0

3 years ago

What is the surface area of the composite figure? Round to the nearest tenth.

alexandr402 [8]

Answer:

2855.0

Step-by-step explanation:

there are several surface areas.

1. outside surface of the cylinder = circle circumference times height = 2*pi*r*height = 2*pi*14*14 = 1231.5

2. top and bottom of the cylinder = circle area times 2 = pi*r^2 * 2 = pi*14^2 *2 = also 1231.5

3. subtract the 2 cut out rectangles on the top and the bottom = 2* 6*14 = 168

4. add the areas of the inside walls of the cut out block.

there are 2 narrow rectangles = 2* 6*14 = 168

there are 2 squares = 2* 14*14 = 392

so, 1.+2.-3.+4. = 2855.0 (2855.00864...)

5 0

3 years ago

Based on these equations, which one represents the greatest rate?

Firdavs [7]

For the 1st one its...

y = 7x + 5.

For the 2nd one its...

Choice C: 32

For the 3rd its...

Choice A: 3/4

3 0

3 years ago