What is -X+42 and 1.3X+49.3 intersection on the graph
1 answer:
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Answer:
x=0
x=10
x=24
Step-by-step explanation:
f(x) = -.05x^2 + x +6
The initial value is 6 ( Let x=0 and f(0) = 6)
f(x) = -.05( x^2 -20 x -120)
I plotted the equation and maximum is at x=10 and the zero is at x=25
