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2 years ago

Omg plzzzzzzzzzzz HELPPPPPPPPPPP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Mathematics

2 answers:

natta225 [31]2 years ago

5 0

Answer:

Step-by-step explanation:

Greeley [361]2 years ago

4 0

Answer:

25!!

Step-by-step explanation:

One side(s) = x+6

Perimeter (4s)= 124

4(x+6) = 124

4x + 24 = 124

4x = 124-24

x = 100/4 = 25

I hope im right!! ;)

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Step-by-step explanation:

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2 years ago

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3 years ago

What is the area of a parallelogram with a base of 10 meters and a height of 5 meters?

Marizza181 [45]

Answer:

50 meters

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2 years ago

Consider the case of a triangle with sides 5, 12, and the angle between them 90°.

Daniel [21]

Answer:

a) Applying Pithagoras Theorem

b) Trigonometric relations

c) No we can not

d) No we can not

e) See step-by-step explanation

f) See step-by-step-explanation

Step-by-step explanation:

a) The easiest method for calculating the missing side is applying Pithagoras Theorem

c² = a² + b²

c² = (5)² + (12)² ⇒ c² = 25 + 144 ⇒ c² = 169 ⇒ c = 13

b) The easiest method to find the missing angles, is to calculate the sin∠ and then look for arcsin fuction in tables.

sin ∠α = 5/13 sin ∠α = 0.3846 ⇒ arcsin (0.3846 ) α = 23⁰

Now we can either get the other angle subtracting 180 - 90 - 23 = 67⁰

Or calculating sinβ = 12 /13 sinβ = 0.9230 arcsin(0.9230) β = 67⁰

c) The law of cosines should not be applied to right triangles, in fact for instance in our particular case we have:

Question a)

c² = a² + b² - 2*a*b*cos90⁰ (law of cosines ) but cos 90⁰ = 0

then c² = a² + b² which is the expression for theorem of Pithagoras

In case you look for calculating the missing angles

c² = a² + b² - 2*5*13*cos α

169 = 25 + 144 - 2*5*13* cos α

As you can see 169 - 25 - 144 = 0

Then we can not apply law of cosine in right triangles, we shoul apply trigonometric relations and Pithagoras theorem, and as we saw you can get the expression of Pithagoras theorem from cosine law

c² = a² + b² - 2*a*b*cos∠90° cos ∠ 90° = 0

Then c² = a² + b²

3 0

3 years ago

A. Write the formula for the area A of a trapezoid. Use b1 and b2 for the lengths of the bases, and use h for the height.

lesya692 [45]

Answer:

(a) The formula for the area A of a trapezoid

$A = \frac{1}{2}(b_{1}+ b_{2})h$

(b) Solve the formula for h

$h = \frac{2A}{b_{1}+b_{2}}$

The height h of the trapezoid is 6 cm.

Step-by-step explanation:

(a) The formula for the area A of a trapezoid

As b₁, b₂ being the lengths of the bases and 'h' is the height.

So, the formula for the area A of a trapezoid

$A = \frac{1}{2}(b_{1}+ b_{2})h$

(b) Solve the formula for h

As the formula for the area A of a trapezoid is

$A = \frac{1}{2}(b_{1}+ b_{2})h$

So, formula for height h of trapezoid

$h = \frac{2A}{b_{1}+b_{2}}$

Using $h = \frac{2A}{b_{1}+b_{2}}$ to find the height h of the trapezoid.

So,

$h = \frac{2A}{b_{1}+b_{2}}$

$h = \frac{2(72)}{16+8}$ ∵b₁ = 16, b₂ = 8, A = 72cm²

$h = \frac{144}{24}$

$h = 6 cm$

So, h = 6 cm

Hence, The height h of the trapezoid will be 6 cm.

Keywords: area of trapezoid, length, base, height

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3 years ago