Jim paddles from one shore of a lake 3 miles wide at 4 mph, and John paddles from the opposite shore a 5 pmh. How long will they
travel before they meet
2 answers:
<span>T = time that each will paddle before they meet </span>
<span>D = distance paddled by JIm </span>
<span>(3 - D) = distance paddled by John </span>
<span>D = 4T --- Equation 1 </span>
<span>and </span>
<span>(3 - D) = 5T or </span>
<span>D = 3 - 5T --- Equation 2 </span>
<span>Since Equation 1 = Equation 2 </span>
<span>4T = 3 - 5T </span>
<span>9T = 3 </span>
<span>T =1/3 hr = 20 minutes </span>
<span>ANSWER -- Jim and John will be paddling for 20 minutes before they pass each other</span>
Let the time they both travel be x hours.
By the time they both meet, the distance covered by both would be equal to the width of the river.
Distance = Speed*time
The 4 mph after x hours would have traveled = 4x
The 5 mph after x hours would have traveled = 5x
Total distance traveled = 4x + 5x = 3
9x = 3
x = 3/9
x = 1/3 hours = 1/3 * 60 minutes = 20 minutes
They would have both traveled 20 minutes as at when they meet.
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