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Oliga [24]
3 years ago
6

A box of buttons contains the same number of each type of button. It contains 220g of buttons

Mathematics
1 answer:
ra1l [238]3 years ago
6 0

Answer:

a) 18 button a buttons are required to fill the bag.

b) 12 button b buttons are required to fill the bag.

c) There are 11 buttons of each type in the box containing 220 g of buttons.

Step-by-step explanation:

Complete Question

Two button types, button a weighing 8 grams and button b weighing 12 grams. The buttons are sold in bags. Each bag contains 144 grams of buttons.

a) How many of button a are needed to fill one bag?

b) How many of button b are needed to fill one bag?

c) A box of buttons contains the same number of each type of button it contains 220g of buttons. How many of each type of button are in the box.

Solution

a) A bag contains 144 grams of buttons.

Button a weighs 8 grams per button.

Total number of button a buttons required to fill up the bag = (144/8) = 18 button a buttons.

b) A bag contains 144 grams of buttons.

Button b weighs 12 grams per button.

Total number of button b buttons required to fill up the bag = (144/12) = 12 button a buttons.

c) A box of buttons weighing 220 g contains the same number of each type of button.

Let this number be n.

This means the Total weight of button a buttons in this box = 8n

total weight of button b buttons in this box = 12n

Sum total of the weight of the buttons = 8n + 12n = 20n

20n = 220

n = (220/20) = 11.

This means there are 11 buttons of each type in the box containing 220 g of buttons.

Hope this Helps!!!

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Answer:

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Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

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After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so \mu = 145, \sigma = 25.

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This is the value of X when Z has a pvalue of 0.90.

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Step-by-step explanation:

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Step-by-step explanation:

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