What is 4/5 | 3 1/2 | and 3 1/8 as a fraction in feet

1 answer:

5 0

A foot is broken up into twelve equal parts called inches. On a tape measure, each inch is divided into sixteenths. To add or subtract, arrange the feet over feet, inches over inches, and any fractions above another. When carrying inches remember there are 12 inches in a foot, and to bor- row a foot gives you 12 inches (not 10!). .. btw it's not the answer to your problem just help solve ..

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If x2+y2 = 12 and x2-y2=18, what is the value of x4-y4?

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Step-by-step explanation: add the equations

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svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
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\\ \quad \\
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\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
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now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

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