Answer: I think number 2 b
Explanation:
Answer:
green is the dominant trait and yellow would only be found in the second generation when 2 passive yellow genes can come together a green or yellow or green w green trait will always be green a pea can only be yellow with 2 recessive yellow genes
Explanation:
The same ligand can bind to different receptors causing different responses (e.g.. acetylcholine). On the other hand, different ligands binding to different receptors can produce the same cellular response (e.g. glucagon, epinephrine).
Answer:
a) The expected phenotype of the F1 plants is 100% RrBb, red kernels.
b) The expected phenotypic classes in the F2 are: 9:3:3:1
9/16 R-B-, 3/16 rrB-, 3/16 R-bb, 1/16 rrbb
Proportions 9:6:1.
9/16 Red kernel (R-B-), 6/16 Brown kernel (rrB- + R-bb), 1/16 White kernel (rrbb)
Explanation:
<u>Available data:</u>
- brown kernel: R-bb or rrB-
1º Cross) RRBB x rrbb
F1) 100% RrBb (red kernels)
2ºCross) RrBb x RrBb
Gametes) RB RB
Rb Rb
rB rB
rb rb
Punnet Square) RB Rb rB rb
RB RRBB RRBb RrBB RrBb
Rb RRBb RRbb RrBB Rrbb
rB RrBB RrBb rrBB rrBb
rb RrBb Rrbb rrBb rrbb
F2) Phenotypic classes:
<em>9/16 R-B-</em>
<em> 3/16 rrB-</em>
<em> 3/16 R-bb</em>
<em> 1/16 rrbb</em>
Phenotypic proportions:
<em>9/16 Red kernel (R-B-)</em>
<em> 6/16 Brown kernel (rrB- + R-bb)</em>
<em> 1/16 White kernel (rrbb) </em>
You are correct the answer is B. Good luck and good job