Answer:
by testcrossing with a homozygous recessive partner
Explanation:
<u>If a pet cockroach exists whose zygosity is unknown, this can be determined by a test cross. A test cross involves crossing an organisms whose zygosity is unknown with a partner that is homozygous recessive for the same trait.</u>
Let us assume that brown body is represented by the allele B, the dominant allele. The homozygous recessive version would be bb.
The genotype of a brown cockroach whose zygosity is not known can be denoted as B_, where '_' can be a 'B' or a 'b'.
When B_ is crossed with bb:
B_ x bb
Progeny
2 Bb
2 _b
The phenotype of Bb would be brown (since B is dominant over b) while the phenotype of _b would depend on the zygosity level of the cockroach.
If the unknown genotype is BB, then _b becomes Bb and the phenotype will be a brown body. This means that all the progeny will appear brown. (<em>see the first attached image for the Punnet's square</em>)
In other word, if the unknown genotype is bb, then _b becomes bb and the phenotype will be a alternate color (non-brown) body. This means that 50% of the progeny will appear brown while the remaining 50% will be in the alternate color. (<em>attached</em>
Answer: A. protein like tubules
B. Microtubules
C. Microfilaments
Explanation:
Cytokinesis in the bacteria is facilitated by the presence of these conserved tubulin-like proteins. Due to the fact that their walls are flexible, constriction of these walls is possible aiding in cytokinesis. Unlike in plant that have rigid cell wall, a cell plate is involved in the formation of a new cell wall between the daughter cells. Network of microtubules determines the position of the cell plate which is mostly like a disc in the middle of the two daughter cells. Cleavage furrow occurs in animal cells which is caused by the action of the contractile ring: a ring of actin microfilament.
<span> Enzymes are usually proteins but some also contain nucleic acids (RNA in particular) and the list of chemical reactions that are catalyzed by RNA has been expanding. So the answer is proteins.</span>
Answer:
All the crossing will be like this after realizing it:
Explanation:
Gl x Gl
GG, Gl, Gl, ll
gl x gl
gg, Lg, Lg, LL
On the first crossing we'll have 50% Gl and both other genotypes will be 25%
On the second crossing we'll have 50% Lg and both other genotypes will be 25%.