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uranmaximum [27]
3 years ago
5

How much air would be needed to fill a bouncy ball with a radius of 9 cm?

Mathematics
2 answers:
Rzqust [24]3 years ago
5 0

The volume of a sphere = (4/3)\pir^3

r = radius

In our problem,

r = 9 cm

To find the volume of this sphere, plug our radius into the volume equation.

V = (4/3)\pi(9)^3 = 972\picm^3

The correct answer is C

mart [117]3 years ago
3 0

Answer: c.

Step-by-step explanation:

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nataly862011 [7]

Answer:

Answer 1; Angles forming a linear sum to 180°

Answer 2; Substitution

Answer 3; Definition of perpendicular lines

Step-by-step explanation:

The two column proof is presented as follows;

Statement  {}                               Reason

1. ∠SWT ≅ ∠TWU {}                    Given

2. m∠SWT + m∠TWU = 180°  {}  Angles forming a linear sum to 180°

3. m∠SWT + m∠SWT = 180° {}    Substitution

4. m∠SWT = 90°  {}                      Algebra

5. \underset{TV}{\leftrightarrow }⊥ \underset{SU}{\leftrightarrow } {}                                  Definition of perpendicular lines

Perpendicular lines are defined as lines that are at right angles (90°) to each other, therefore given that the angle formed by the lines \underset{TV}{\leftrightarrow } and \underset{SU}{\leftrightarrow } m∠SWT = 90°, therefore, the lines \underset{TV}{\leftrightarrow } and \underset{SU}{\leftrightarrow } are perpendicular to each other.

3 0
3 years ago
Quadrilateral DEFG has vertices D(−2,4) , E(4,7) , F(10,3) , and G(8,0) .
fredd [130]

A rotation 270° counterclockwise about the origin is the same as rotation 90° clockwise about the origin and has a rule:

(x,y)→(y,-x).

Then:

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  • E(4,7)→E'(7,-4)
  • F(10,3)→F'(3,-10)
  • G(8,0)→G'(0,-8)

Answer: the coordinates of vertices of quadrilateral D′E′F′G′ are D'(4,2), E'(7,-4), F'(3,-10), G'(0,-8).

8 0
3 years ago
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GrogVix [38]

Answer:

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Step-by-step explanation:

Let the side of the square cut from the cardboard be “x”

Size of the square base = 12 -2x, height of the box = x

Volume of square box = Area * height = (12-2x)^2 * x

Differentiating the above equation and equating it to zero, we get –  

d/dx ((12-2x)^2 * x)

d/dx{(144 + 4x^2 -48x)*x}= d/dx (144x + 4x^3 -48x^2)

d/dx (144x + 4x^3 -48x^2) = 0

144+8x^2-96X= 0\\18 +X^2-12X = 0

On solving above equation, we get –  

x=6+3\sqrt{2}  \\ x=6-3\sqrt{2}

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3 years ago
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