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3 years ago

What is the value of x

Mathematics

1 answer:

ycow [4]3 years ago

8 0

Answer:

Step-by-step explanation:

x + 131 + 108 + 107 + 110 = 540

x + 456= 540

x = 84

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Create triangle A’B’C by reflecting triangle ABC over the y-axis on the coordinate plane. What are the new coordinates of the ve

pickupchik [31]

Answer:

Step-by-step explanation:

When talking about reflection, we usually mean reflecting across a line, or axis. Reflecting a shape means looking at the mirror image on the other side of the axis. Consider the point (x,y), if you reflect this point across the y-axis you should multiply the x-coordinate by -1, so you get:

$(x,y)\rightarrow(-x,y)$

For triangle ABC we have:

$A(-4,2) \\ \\ B(-1,3) \\ \\ C(-1,-4)$

Therefore, the reflecting points are:

$A'(4,2) \\ \\ B(1,3) \\ \\ C(1,-4)$

Both the original triangle and the reflected one are shown below.

8 0

3 years ago

Is this a parallelogram and why?

oksano4ka [1.4K]

the rectangle is but the line is not because the line has to have another side !

3 0

3 years ago

Read 2 more answers

Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$