Answer:
5/6 +5/6 = 10/6 = 1 2/3 glasses of juice
Step-by-step explanation:
Answer:
uhhhhhhhhhhhhhhhhh
Step-by-step explanation:
i wish i knew
That funky circle in the middle is the composition of the function. It asks you to take a function as an input and to yield an output that's another function. It's one of the five function operations, along with adding, subtracting, multiplying, and dividing.
When you compose, you might find the notation w(u(x)) easier to understand. It's saying evaluate u then evaluate w.
For our functions, the compositions are:
u(w(x)) = u(2x²) = -(2x²) - 2 = -2x² - 2
w(u(x)) = w(-x - 2) = 2(-x - 2)² = 2(x² + 4x + 4) = =2x²+ 8x +8
Now we evaluate each composition at 4.
u(w(4)) = -2(4²) - 2 = -2(16) - 2 = -32 -2 = -34
w(u(4)) = -2(2²) +8(2) + 8 = -2(4) + 16 + 8 = -8 + 16 + 8 = 16.
Thus, u(w(4)) = -34 and w(u(4)) = 16.
Answer:
15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 25 charged purchases and a standard distribution of 2
This means that 
Proportion above 27
1 subtracted by the pvalue of Z when X = 27. So



has a pvalue of 0.8413
1 - 0.8413 = 0.1587
Out of the total number of cardholders about how many would you expect are charging 27 or more in the study?
0.1587*100% = 15.87%
15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.
Answer:
i'm pretty sure the one you have selected in the photo is right
Step-by-step explanation: