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2 years ago

Need help ASAP Have a nice rest of your day -Mellow

Mathematics

2 answers:

Semenov [28]2 years ago

7 0

Answer:

Step-by-step explanation:

y-intercept: starting point. Find y value when x is 0. It's 3.

Slope: rise over run. Find point to point and count rise and run. rise is 4 and run is 1. So it's 4/1 which is 4.

Correct answer is C.

VMariaS [17]2 years ago

5 0

Answer:

option c

Step-by-step explanation:

first, find the y-intercept:

the y-intercept is the point where the line intersects at the y-axis, in this case, at 3.

therefore, we can rule out all options except c, sincee the y-intercept is 3

hope this helps :)

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2 years ago

On the way home from school, Ross wears his 20-pound backpack and carries his 7-ounce lunchbox. How many ounces does he carry in

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3 years ago

Type the expression that results from the following series of steps:

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Answer:

$\frac{x - 3}{6}$

Step-by-step explanation:

First, subtract 3 from x

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2 years ago

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 108.7-cm and a standard dev

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Let x be the lengths of the steel rods and X ~ N (108.7, 0.6)

To get the probability of less than 109.1 cm, the solution is computed by:

z (109.1) = (X-mean)/standard dev

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= 1.1/0.6

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3 years ago

A real estate company wants to build a parking lot along the side of one of its buildings using 800 feet of fence. If the side a

Elden [556K]

Answer:

80,00 $ft^{2}$

Step-by-step explanation:

According to my research, the formula for the Area of a rectangle is the following,

$A = L*W$

Where

A is the Area
L is the length
W is the width

Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>

800 / 2 = 400ft

So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.

400/2 = 200 ft

Now we can calculate the maximum Area using the values above.

$A = 400ft*200ft$

$A = 80,000ft^{2}$

So the Maximum area we are able to create with 800 ft of fencing is 80,00 $ft^{2}$

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Read more on Brainly.com - brainly.com/question/12953427#readmore

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2 years ago