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zhannawk [14.2K]
3 years ago
10

Please help me! Thank you

Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

Anne

Step-by-step explanation:

The expression cannot be simplified anymore, but it can be laid out correctly.

The greatest number for the exponents should come first, so Anne is the one who laid it out correctly.

Hope it helps!!

Let me know if I'm wrong...

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and lines will head towards the origin if constraint satisfied by putting x= 0, y=0

and on the contrary lines will move away from origin when condition of constraint does not satisfied.

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The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2617 and standard deviation
Eduardwww [97]

Answer:

a) N(2617, 586)

b) 0.3613 = 36.13% probability that the customer consumes less than 2409 calories.

c) 0.4013 = 40.13% of the customers consume over 2764 calories

d) 3981 calories.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 2617, \sigma = 586

a. What is the distribution of X?

Here we first place the mean, then the standard deviation.

N(2617, 586)

b. Find the probability that the customer consumes less than 2409 calories.

This is the pvalue of Z when X = 2409. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2409 - 2617}{586}

Z = -0.355

Z = -0.355 has a pvalue of 0.3613

0.3613 = 36.13% probability that the customer consumes less than 2409 calories.

c. What proportion of the customers consume over 2764 calories?

This is 1 subtracted by the pvalue of Z when X = 2764. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2764 - 2617}{586}

Z = 0.25

Z = 0.25 has a pvalue of 0.5987

1 - 0.5987 = 0.4013

0.4013 = 40.13% of the customers consume over 2764 calories

d. The Piggy award will given out to the 1% of customers who consume the most calories. What is the fewest number of calories a person must consume to receive the Piggy award?

Top 1%, so the 100-1 = 99th percentile.

The 99th percentile is the value of X when Z has a pvalue of 0.99. So it is X when Z = 2.327. So

Z = \frac{X - \mu}{\sigma}

2.327 = \frac{X - 2617}{586}

X - 2617 = 2.327*586

X = 3980.6

Rounding to the nearest calorie, 3981 calories.

7 0
3 years ago
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