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labwork [276]
3 years ago
8

I have to find the value of x please help me will give brainliest to correct answer​

Mathematics
1 answer:
Semenov [28]3 years ago
7 0

Answer:

C. x = 5

Step-by-step explanation:

48 = 7x + 13

-13           -13

35 = 7x

5 = x

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9

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Answer:

9. Force is required to change an object velocity.Force is equal to mass times acceleration.

10.  Force acting on object are paired with equal and opposite forces

Step-by-step explanation:

9.

Newton's 2nd law states that force is a product of mass and acceleration.In this case, the force of friction is causing deceleration of the ball.This is an example of rolling friction.Acceleration of the ball depends directly on this friction but indirectly on its mass.

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From Newton's 3rd Law ,for every action there is an equal and opposite reaction.The astronaut throwing the ball will experience the effect of an external force againts his own which is equal  and  in the opposite direction to the force she applied.This is why the astronaut moves backward but slower.

3 0
3 years ago
I need the answer for numbers 1-4 to see if I’m correct. Anyone know?
svetlana [45]
They are all correct good job
8 0
3 years ago
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mamaluj [8]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
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