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choli [55]
3 years ago
9

Which category best describes this group of shapes?

Mathematics
1 answer:
Effectus [21]3 years ago
6 0

Answer:

I think it's parallelograms.....

Step-by-step explanation:

Parallelograms; a four-sided plane rectilinear figure with opposite sides parallel.

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What should be done to x^2 + 15x in order to create a perfect square?
lana [24]

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2 \\\\[-0.35em] ~\dotfill

\bf x^2+15x+\boxed{?}^2\implies \stackrel{\textit{we know the middle term is}}{2\sqrt{x^2}\cdot \sqrt{\boxed{?}^2}\implies 2x\boxed{?}}\qquad then\qquad 2x\boxed{?}=15x \\\\\\ \boxed{?}=\cfrac{15x}{2x}\implies \boxed{?}=\cfrac{15}{2}\qquad \impliedby \textit{we should add that much \underline{squared}} \\\\[-0.35em] ~\dotfill\\\\ x^2+15x+\left( \cfrac{15}{2} \right)^2\implies \left(x+ \cfrac{15}{2} \right)^2

5 0
3 years ago
Algebra 2 Quadratics. <br>Maximum Height of<br> h(t) = -16t + 96t<br>(with steps if possible)
JulijaS [17]

Answer:

max. height = 240

Step-by-step explanation:

Function should be h(t ) = - 16t² + 96t

find the zeros by solving h(t) = 0

- 16t² + 96t = 0 ( take out common factor - 16t )

- 16t(t - 6) = 0

equate each factor to zero and solve for t

- 16t = 0 ⇒ t = 0

t - 6 = 0 ⇒ t = 6

the maximum vertex is at the midpoint of the zeros

t = \frac{0+6}{2} = 3

h(3) = (- 16 × 3) + (96 × 3) = - 48 + 288 = 240 ← max. height


3 0
3 years ago
For every 5 red flowers in my garden, there are 10 yellow flowers. There are 81 flowers in my garden in total (red and yellow fl
omeli [17]

Answer:

8 red flowers and 40 yello flowers

Step-by-step explanation:

7 0
2 years ago
Graph the equation. <br><br> y= -1/6x-3
Harman [31]
One coordinate is (0,3) and another is (2,6)
4 0
3 years ago
I know someone smart is out there that could answer this question. it is 9th grade Algebra if you dont know that dont click.
faust18 [17]

Answer:

1. d-even lc- -

2. d- odd lc- +

3. type- odd lc- +

4. type- even lc- -

5. d- even lc- - type even

6 d- odd lc- + type- even

Step-by-step explanation:

when the degree is odd, one leg goes down one goes up

when the degree is even, both legs go up or down

when the leading coefficient is negative the end behavior is -∞

when the leading coefficient is positive, the end behavior ∞

a function is odd when both legs go down

a function is even when the legs go in different directions

a function is neither when it isn't a function (think vertical line test)

4 0
3 years ago
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