How do you do this?<br> it’s similar figures with line segments

For which of the following inequalities is x≥4 a solution.<br> x+3≥1<br> 3x≥1<br> x-3≥1

pychu [463]

Answer:

x - 3 ≥ 1

Step-by-step explanation:

Solving each of the inequalities

x + 3 ≥ 1 ( subtract 3 from both sides )

x ≥ - 2

3x ≥ 1 ( divide each inequality by 3 )

x ≥ $\frac{1}{3}$

x - 3 ≥ 1 ( add 3 to both sides )

x ≥ 4 ← required solution

5 0

2 years ago

Read 2 more answers

A consulting firm has received 2 Super Bowl playoff tickets from one of its clients. To be fair, the firm is randomly selecting

Soloha48 [4]

Answer:

Therefore the only statement that is not true is b.)

Step-by-step explanation:

There employees are 6 secretaries, 5 consultants and 4 partners in the firm.

a.) The probability that a secretary wins in the first draw

= $\frac{number \hspace{0.1cm} of \hspace{0.1cm} secreataries}{total \hspace{0.1cm} number \hspace{0.1cm} of \hspace{0.1cm} employees} = \frac{6}{15}$

b.) The probability that a secretary wins a ticket on second draw. It has been given that a ticket was won on the first draw by a consultant.

p(secretary wins on second draw | consultant wins on first draw)

= $\frac{p((consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)\cap( secretary\hspace{0.1cm} wins\hspace{0.1cm} on second \hspace{0.1cm}draw))}{p(consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)}$

= $\frac{\frac{5}{15} \times \frac{6}{14}}{\frac{5}{15} } = \frac{6}{14}$ .

The probability that a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw = $\frac{6}{15}$ is not true.

The probability that a secretary wins on the second draw = $\frac{number \hspace{0.1cm} of \hspace{0.1cm} secretaries \hspace{0.1cm} remaining } { number \hspace{0.1cm} of \hspace{0.1cm} employees \hspace{0.1cm} remaining} = \frac{6 - 1}{15 - 1} = \frac{5}{14}$

c.) The probability that a consultant wins on the first draw =

$\frac{number \hspace{0.1cm} of \hspace{0.1cm} consultants \hspace{0.1cm} } { number \hspace{0.1cm} of \hspace{0.1cm} employees \hspace{0.1cm} } = \frac{5 }{15} = \frac{1}{3}$

d.) The probability of two secretaries winning both tickets

= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)

= $\frac{6}{15} \times \frac{5}{14} = \frac{1}{7}$

Therefore the only statement that is not true is b.)

5 0

3 years ago

Solve for x: 6(4x+5)=3(x+8)+3 round to nearest hundredth

Hitman42 [59]

Solve for x by simplifying both sides of the equation then isolating teh varible.
your answer = - 1/7

3 0

3 years ago

Can someone please answer this question please help please answer it correctly and please show work please help I need it please

mr_godi [17]

Answer:

Step-by-step explanation:

24)

200= 3(21) + 4x

200= 63 +4x

-63 -63

137= 4x

divide each side by 4

34 = x

c

25)

.5(pi)= about 1.6

1.6(2.5)= 4

c

44)

equation- T= 12.17+0.75v

105.75= 12.17 + .75v

-12.17 -12.17

93.58= .75v

divide each side by .75

answer 125

3 0

2 years ago

Read 2 more answers

Consider a t distribution with 7 degrees of freedom. Compute P(-1.29 < t < 1.29). Round your answer to at least three deci

marusya05 [52]

Answer:

Step-by-step explanation:

Given that there is a t distribution with 7 degrees of freedom.

P(-1.29 < t < 1.29)=1-0.2380

=0.7620

b) Now there is a different t distribution with 18 df.

When $P(t\leq c)=0.05$

c=-1.733

7 0

2 years ago

How do you do this? it’s similar figures with line segments