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Damm [24]
4 years ago
8

In , the world's largest pumpkin weighed kilograms. An average-sized pumpkin weighs grams. The world-record pumpkin weighs blank

kilograms more than an average-sized pumpkin. The solution is_______
Mathematics
1 answer:
In-s [12.5K]4 years ago
3 0

Answer:

Complete question statement is;

n 2009, the worlds largest pumpkin weighed 1,725 kilograms. An average sized pumpkin weighs 5000 grams. The 2009 world record pumpkin weighs ___ kilograms more than the average sized pumpkin

Step-by-step explanation:

The answer to this is that world record pumpkin weighs 1720 kilograms more than the average sized pumpkin

In one kilogram, there are 1,000 grams i

so 5,000 grams means to be equivalent to 5 kilograms.

Now since we are in same metric units, we can now compare the largest weight and the average weight which would be;

= 1725 - 5

= 1720 kilograms

So the difference between largest weighed and average weighed pumpkin is 1720 kilograms

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Mhanifa please help i will mark brainliest
ioda

Answer:

<u>Use Pythagorean:</u>

  • a² + b² = c²
<h3>#1</h3>
  • x² = 16² - 8²
  • x² = 192
  • x = √192
  • x = 12.73, not an integer

<u>Not a Pythagorean triple</u>

<h3>#2</h3>
  • x² = 40² + 9²
  • x² = 1681
  • x = √1681
  • x = 41

<u>It is a Pythagorean triple (9, 40, 41)</u>

<h3>#3</h3>
  • x² = 6² + 13²
  • x² = 205
  • x = √205
  • x = 14.32, not an integer

<u>Not a Pythagorean triple</u>

4 0
3 years ago
Someone please help me answer this!!
aivan3 [116]

Answer:

8 units is the answer.

Step-by-step explanation:

Pythagorean theorem can be written as,

d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\\\d=\sqrt{(9-9)^2 + (-7-1)^2}\\\\d=\sqrt{(0\\)^2+(-8)^2} \\\\d=\sqrt{64} \\\\d=8

∴ d = 8 units

3 0
3 years ago
The weight of laboratory mice follows a normal distribution, with a mean of 0.68 ounce and a standard deviation of 0.02 ounce. W
elena-14-01-66 [18.8K]

Answer:

A.99.7%

Step-by-step explanation:

We are given;

  • Mean of a distribution, μ as 0.68 ounce
  • Standard deviation, σ as 0.02 ounce
  • The range values of X between 0.62 ounce and 0.74 ounce

We are required to calculate the percentage of the weight to be between 0.62 ounce and 0.74 ounce

Step 1: Calculate the Z-score

To get the Z-score we use the formula;

Z-score = (x-μ)/σ

Therefore, when x = 0.62

Then z score = (0.62 - 0.68 ) ÷ 0.02

                     = -3

When, x = 0.74

Then, Z score = (0.74 - 0.68) ÷ 0.02

                       = 3

Step 2:  we use the Z-score table or the empirical rule

Using the Z-score table;

P(-3 < z < 3) = 99.7%.

Therefore; the percentage of mice that weigh between 0.62 ounce and 0.74 ounce is 99.7%.

7 0
3 years ago
Avi's pet hamster chubby loves to run in his hamster wheel. during one "race", avi counts 100 rotations of the wheel. she wants
yKpoI14uk [10]
If the diameter is 8 inches, the circumference is 8π inches.  So if the pet turned the wheel 100 revolutions the distance traveled is:

d=100(8π) inches

d=800π inches

d≈2513.27 inches
5 0
3 years ago
Read 2 more answers
Vary the scale factor n from values less than 1 to values greater than 1. How do the points in the resulting images differ from
olya-2409 [2.1K]

Answer: For values of n < 1, all the points on the image move closer to the center of dilation and the logo shrinks. For values of n > 1, all the points on the image move farther from the center of dilation and the logo expands.

Step-by-step explanation: PLATO sample answer. hope it helps :)

5 0
3 years ago
Read 2 more answers
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