A square storage bin that measures 15 feet on a side is filled with corn. If 1 bushel fits in 1.25 cubic feet, how many bushels
2 answers:
Answer:
2700 bushels
Step-by-step explanation:
First of all we have to calculate the square storage bin volume:
Square storage bin volume= Side*Side*Side
<em>Remember that in a square storage bin (cube) the sides are the same length.</em>
Then:
Square storage bin volume= Side*Side*Side
Square storage bin volume= 15 feet*15 feet*15 feet
Square storage bin volume= 3375
We know that 1 bushel fits in 1.25 cubic feet, then in order to calculate how many bushels the square storage bin contain:
3375 * (1 bushel)/(1.25
)
2700 bushels
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First, find the vertices of the shaded region. You can do this my graphing or by solving a system of equations for each pair of functions. <em>I am going to find them by graphing.</em>
x ≥ 0 and y ≥ 0 place the shaded region in the first quadrant with a vertex at (0, 0)
now graph y ≤ 3. a vertex is at (0, 3)
now graph y < -2x + 5. a vertex is at (1, 3). the other vertex is the x-intercept (when y = 0).
0 = -2x + 5
-5 = -2x
So, the vertex is
Next, input the coordinates of the vertices into the objective function.
C = -6x + 5y
(0, 0): C = -6(0) + 5(0)
= 0 + 0
= 0
(0, 3): C = -6(0) + 5(3)
= 0 + 15
= 15
(1, 3): C = -6(1) + 5(3)
= -6 + 15
= 9
: C = -6(\frac{5}{2}[/tex]) + 5(2)
= -15 + 10
= -5
The maximum is C = 15 which occurs at vertex (0, 3)
Answer: A
Answer:
There is no evidence that there is no significant difference between the sample means
Step-by-step explanation:
given that a statistics instructor who teaches a lecture section of 160 students wants to determine whether students have more difficulty with one-tailed hypothesis tests or with two-tailed hypothesis tests. On the next exam, 80 of the students, chosen at random, get a version of the exam with a 10-point question that requires a one-tailed test. The other 80 students get a question that is identical except that it requires a two-tailed test. The one-tailed students average 7.81 points, and their standard deviation is 1.06 points
The two-tailed students average 7.64 points, and their standard deviation is 1.33 points.
Group One tailed X Two tailed Y
Mean 7.8100 7.6400
SD 1.0600 1.3300
SEM 0.1185 0.1487
N 80 80
(Two tailed test)
The mean of One tailed X minus Two tailed Y equals 0.1700
t = 0.8940
df = 158
p value =0.3727
p is greater than alpha 0.05
There is no evidence that there is no significant difference between the sample means