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4 years ago

Does anyone know how to solve (2 Times x) + 5 =31

Mathematics

2 answers:

Anika [276]4 years ago

8 0

X = 13 hope it helped

Katarina [22]4 years ago

8 0

I think it’s 13 hope you get it right

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A Child’s Growth and Prosperity

MArishka [77]

Answer:

a) 0.75 inch/month

b) y-20 = 0.75(x-4)

c) 17 inches

d) 44

a) 0.8 inch/month

b) yes

c) y = 0.8x + 18.8

d) 18.8 inches

Step-by-step explanation:

a) (21.5-20)/(6-4) = 1.5/2

= 0.75 inch/month

If this is correct, 2 months after the 6th month (month 8), it should be

21.5 + 2(0.75) = 23

Which it is

b) y-y1 = m(x-x1)

Where y is the length, x is the months, m is the slope and (x1,y1) is a known point

At x = 4, y = 20

y-20 = 0.75(x-4)

y = 0.75x + c

20 = 0.75(4) + c

c = 20 - 3 = 17

y = 0.75x + 17

c) at birth, 4 months before month 4

So, 20 - 0.75(4) = 17

Which is also the y-intercept

d) y = 0.75(36) + 17

y = 27 + 4 = 44 inches

Generally, at the age of 3 years (36 month) the length is between 35 and 40 inches

a) slope = (30-22)/(14-4)

= 0.8 inch/month

b) 0.8 > 0.75, so yes

c) When x = 4, y = 22

y-22 = 0.8(x - 4)

y - 22 = 0.8x - 3.2

y = 0.8x + 18.8

y-intercept is 18.8

d) at birth, x = 0.

Length was 18.8 inches

Step-by-step explanation:

6 0

2 years ago

Multiply the binomials: (x+3)(2x-5)

gulaghasi [49]

The answer I got is (2x^2+x-15)

5 0

3 years ago

3/8 divided by 13/16

dedylja [7]

Answer:

Fraction= 6/13

Decimal= 0.4615

8 0

3 years ago

Read 2 more answers

A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c

olchik [2.2K]

The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in $E^{c}$ . Find $P(E^{c})$ .

Solution:

Part 1:

$E^{c}$ means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

$E^{c}=S-E \\ \\ 
E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\ \\ 
E^{c}=(4,5,6)$

Thus the set compliment of E will contain the elements {4,5,6}.So

$E^{c}$ = {4,5,6}

Part 2)

$P(E^{c})$ means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

$P(E^{c})$ = (Number of Elements in $E^{c}$ )/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set $E^{c}$ = $n(E^{c})$ =3

So,

$P(E^{c})= \frac{n(E^{c}) }{n(S)} \\ \\ 
P(E^{c})= \frac{3}{12} \\ \\ 
P(E^{c})= \frac{1}{4}$

7 0

3 years ago

PLEASE ANSWER CORRECTLY, I WILL GIVE BRAINLIEST <3 THANKS IN ADVANCE!

guajiro [1.7K]

Answer:

1 : 15

2: 12

3: 52

4: 27.3

Step-by-step explanation:

For #1:

if line m and n are perpendicular then they will create right angles

Right angles have a measure of 90 degrees

That being said we can find the measure of the missing angle by subtracting the measure of the known angle (75) from 90

so k = 90 - 75

90 - 75 = 15

Hence k = 15.

For #3 ( very similar to #1, only difference is the values of the angles )

so R = 90 - 38

90 - 38 = 52

Hence, R = 52

For #2 and #4

Complementary angles have a sum of 90°

So like the previous questions we can find the measure of the missing angle by subtract the measure of the given angle from 90

∠V = 90 - 78

90 - 78 = 12

Hence ∠V = 12

∠Y = 90 - 62.7

90 - 62.7 = 27.3

Hence ∠Y = 27.3

6 0

2 years ago