Does anyone know how to solve (2 Times x) + 5 =31

tankabanditka [31]

The number of candies that will be left over after giving everyone an equal amount is equal to 23.

Given the following data:

Total number of candy = 320 pieces

Number of classmates = 27 classmates

To calculate the number of candies that will be left over after giving everyone an equal amount:

In this exercise, you're required to determine the number of candies Phillipe would have as left over after giving everyone in his class an equal amount of candies.

<h3>How to solve this word problem.</h3>

Thus, we would find the number of times 27 would divide 320 without any remainder.

$\frac{320}{27} = 11 \frac{23}{27}$

From the mixed fraction, we can deduce that the remainder is 23.

Therefore, the number of candies that will be left over after giving everyone an equal amount is equal to 23.

Read more on word problems here: brainly.com/question/13170908

4 0

2 years ago

How did you compute sums of dollar amounts that were not whole numbers? For example, how did you compute the sum of$5.89 and$1.4

nignag [31]

Answer:

$7.34

Step-by-step explanation:

To compute sum of dollars that are not whole numbers. Using the sum of$5.89 and$1.45 as an illustration :

$5.89 + $1.45

Taking the whole numbers first:

$5 + $1 = $6

Take the sum of the decimals :

$0.89 + $0.45 = $1.34

Sum initial whole + whole of sum of decimal

$6 + $1 = $7

Remaining decimal : $1.34 - $1 = $0.34

$7 + $0.34 = $7.34

4 0

3 years ago

Read 2 more answers

At a farm the ratio of cows to horses was 9:2. if there were 72 cows at the farm, how many horses were there?

OLga [1]

ratio of 9:2

means for every 9 cows there are 2 horses

72/9 = 8

8 x 2 = 16

there are 16 horses

4 0

3 years ago

Read 2 more answers

Identify the transformation of the function f(x)=|x| by observing the equation of the function g(x)=|x+3|

Alla [95]

Answer:

a horizontal translation by 3 units left

Step-by-step explanation:

f(x)= |x|

we are given with absolute function f(x)

g(x) = |x+3|

To get g(x) from f(x) , 3 is added with x

If any number is added with x then the graph of the function move to the left

Here 3 is added with x, so the graph of f(x) moves 3 units left to get g(x)

So there will be a horizontal translation by 3 units

6 0

3 years ago

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: $H_0: \mu \leq 10$

The alternative hypothesis is: $H_1: \mu > 10$

b)

The critical value is: $t_c = 1.74$

The decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

c)

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of at most 10 pounds, that is:

$H_0: \mu \leq 10$

At the alternative hypothesis, it is tested if the mean loss is of more than 10 pounds, that is:

$H_1: \mu > 10$

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a significance level of 0.05 and 18 - 1 = 17 df.

Hence, using a calculator for the t-distribution, the critical value is: $t_c = 1.74$ .

Hence, the decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Item c:

We have the standard deviation for the sample, hence the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem, we have that:

$\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18$

Thus, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}$

$t = 1.41$

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0

3 years ago