All categories

3 years ago

To show that the triangles are congruent, triangle ABC could be transformed by

Mathematics

2 answers:

Sladkaya [172]3 years ago

5 0

Answer: A rotation of 270° clockwise about the origin followed by translation left 1 and up 10

Step-by-step explanation:

tekilochka [14]3 years ago

3 0

Answer:

D a reflection over the x axis by a reflection over the y axis

Step-by-step explanation: if u put the triangle on the button left up then move it to the upper right it’s congruent.

You might be interested in

A curve along a highway is to be designed for cars moving at 100 kilometers per hour. Find the angle of banking if the radius of

statuscvo [17]

Answer:

hope this will help you

Step-by-step explanation:

.........

5 0

3 years ago

What two prime numbers make 36.

prohojiy [21]

$5+31=36\\\\7+29=36\\\\13+23=36\\\\17+19=36$

3 0

3 years ago

Eight randomly selected customers at a local grocery store spent the following amounts on groceries in a single visit: $216, $18

chubhunter [2.5K]

Answer:

a) 910

b) 828100

c) 144320

Step-by-step explanation:

a. ∑y

This is the sum of all values of y. So

$\sum y = 216 + 184 + 35 + 92 + 142 + 175 + 9 + 57 = 910$

b. (∑y)^2

This is the square of the sum, so the square of 910, that we found in the previous item.

910² = 828100

c. ∑y^2

This is the sum of the squares of each amount spent. So

$\sum y^2 = 216^2 + 184^2 + 35^2 + 92^2 + 142^2 + 175^2 + 9^2 + 57^2 = 144320$

8 0

3 years ago

Urgent!! please help )):

alisha [4.7K]

The 16th term is: 53

Further explanation:

We have to find the general formula first

The general form is:

$a_n=a_1+(n-1)d\\Given\\a_1=8\\d=3\\Putting\ the\ values\ in\ the\ formula\\a_n=8+(n-1)(3)\\a_n=8+3n-3\\a_n=5+3n\\For\ 16th\ term, put\ n=16\\a_n=5+3(16)\\a_n=5+48\\a_n=53$

The 16th term is: 53

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

#LearnwithBrainly

4 0

3 years ago

Can someone please explain how to get the answer I've watched multiple videos on implicit derivatives and I still cant figure it

Arisa [49]

We're given the implicit equation

x² + 2x + y² - 4y = 12

where "implicit" means that one of the variables is considered a function of the other. In this case, the variable y = y(x) depends on the value of the variable x - in other words, the possible values of y are implied by the value of x. We then say that this equation defines y as an implicit function of x.

We're also given the implicit derivative,

dy/dx = (-2x - 2)/(2y - 4)

which tells us the rate of change y as a function of both x and y. The value of dy/dx corresponds to the slope of the tangent line to the curve defined by the implicit equation above at some point (x, y).

The tangent line is horizontal when its slope is zero. This happens when

(-2x - 2)/(2y - 4) = 0

If y ≠ 2, then we can eliminate the denominator and we're left with

-2x - 2 = 0

Solve for x :

-2x = 2

x = -1

This tells us that the points on the curve with x-coordinate -1 have a tangent line to the curve that is horizontal.

The tangent line is vertical when its slope is undefined/infinite, or equivalently when the denominator of dy/dx is zero:

2y - 4 = 0

Solve for y :

2y = 4

y = 2

So any point on the curve with y-coordinate 2 will have a tangent line there that is vertical.

By completing the square in the implicit equation, we can easily identify where these points are located.

x² + 2x + y² - 4y = 12

x² + 2x + 1 + y² - 4y + 4 = 17

(x + 1)² + (y - 2)² = 17

This equation defines a circle centered at (-1, 2) with radius √17. When x = -1, we have

(y - 2)² = 17 ⇒ y = 2 ± √17

and when y = 2, we have

(x + 1)² = 17 ⇒ x = -1 ± √17

See the attached plot to see the circle and the tangents at these points.

7 0

2 years ago