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3 years ago

12

A curve along a highway is to be designed for cars moving at 100 kilometers per hour. Find the angle of banking if the radius of

the curve is 200 m.

1 answer:

statuscvo [17]3 years ago

5 0

Answer:

hope this will help you

Step-by-step explanation:

.........

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The granola summer buys used to cost $6.00 per pound but it has been marked up %15 A. How much did it cost summer to buy 2.6 pou

Maksim231197 [3]

The granola summer buys used to cost $6.00 per pound but it has been marked up %15 Question: How much did it cost summer to buy 2.6 pounds of granola at the old price.=> previous price of granola = 6.00 dollars per pound=> marked up 15% = 15% /100% = .15Solve:=> 6 * .15 = .9=> 6 + .9 = 6.9 dollars per poundNow, you want to buy 2.6 pounds=> 6.9 * 2.6 = 17.94 dollars <span>
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2 years ago

Helppppppp pleaseee

Viktor [21]

Answer:

$x=2\sqrt{5}$

Step-by-step explanation:

If that is a square, then all sides are the same. Therefore, it's a $\sqrt{10}$ by $\sqrt{10}$ shape. We'll use Pythagorean Theorem to find the diagonal.

$a^2+b^2=c^2\\\sqrt{10}^2+ \sqrt{10}^2=x^2\\10+10=x^2\\20=x^2\\\sqrt{20}=x\\\sqrt{4*5}=x\\ 2\sqrt{5}=x$

Since it's not a fraction, there is no denominator to rationalize. Let me know if you have any other questions!

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2 years ago

What are the answer for these questions?

Burka [1]

Answer:

1. yes

2. 3

3. 1x

4. y=1x+3 or y=x+3

Step-by-step explanation:

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2 years ago

I NEED A PROFESSIONAL ON MATH PROBLEMS NOW!!

BARSIC [14]

Answer:

$62

Step-by-step explanation:

hope this helped!

p.s it would be cool if you gave me brainliest.

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2 years ago

Log_{7 }(5 - 3x)<br>Find the derivative

V125BC [204]

Let <em>y</em> be the expression you want to differentiate:

$y=\log_7(5-3x) \implies 7^y=5-3x$

Now,

$7^y=e^{\ln(7^y)}=e^{y\ln(7)}$

Use the chain rule to differentiate both sides with respect to <em>x</em> :

$\ln(7)e^{y\ln(7)}\dfrac{\mathrm dy}{\mathrm dx}=-3$

Solve for d<em>y</em>/d<em>x</em> :

$\ln(7)7^y\dfrac{\mathrm dy}{\mathrm dx}=-3$

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac3{\ln(7)7^y}$

$\dfrac{\mathrm dy}{\mathrm dx}=\boxed{-\dfrac3{\ln(7)(5-3x)}}$

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2 years ago