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Juli2301 [7.4K]
3 years ago
7

What is the surface area?

Mathematics
2 answers:
ozzi3 years ago
7 0

Answer:

108.37

Step-by-step explanation:

Give me Brainllest T-T

anyanavicka [17]3 years ago
3 0

Answer:

D 108.37

Step-by-step explanation:

You might be interested in
ZX and zy are supplementary angles. zy measures 33°.what is the measure of ZX
Sati [7]

Answer:

147°

Step-by-step explanation:

supplementary angles equal to 180° in total so...

180 - 33 = 147

8 0
3 years ago
BRAINLIEST if right!
Brilliant_brown [7]
Y=-1/3x-1.
Hope this helps!
5 0
3 years ago
Nick can read 3 pages in 1 minute. write the ordered pairs for nick reading 0,1,2 and 3 min
Elis [28]
For 0 minutes, it would be 0 minutes (obviously)
for 1 minute, it would be 3
for 2 minutes, it would be 6 pages
and finally, 3 minutes, will be 9.
to get the answers, you would just have to add 3, since every minute, nick reads 3 pages.
4 0
4 years ago
Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ
-Dominant- [34]

Answer:

\tan(\beta)

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)

\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }

\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}

\sin(\beta) *\dfrac{1 }{\cos(\beta) }

\dfrac{\sin(\beta)}{\cos(\beta) }

Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

8 0
2 years ago
What does 2 (p -q) +5 (p+q) equal when p = 7 and q = -2? Answer:​
salantis [7]

Answer:

43

Step-by-step explanation:

Given

2(p - q) + 5(p + q) ← substitute p = 7 and q = - 2 into the expression

= 2(7 - (- 2)) + 5(7 + (- 2))

= 2(7 + 2) + 5(7 - 2)

= 2(9) + 5(5)

= 18 + 25

= 43

7 0
3 years ago
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