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8090 [49]
2 years ago
15

john and peter started jogging from the same place at the same time, but in opposite directions along a straight road. After jog

ging for 3 hours, they were 27 km apart. If john's average speed was 6 km/h, what is peters speed?
Mathematics
2 answers:
Ray Of Light [21]2 years ago
8 0

Answer:

3 km/h

Step-by-step explanation:

Distance = speed x time

The distance apart equals to the sum of the distance that John jogged, and the distance that Peter jogged since they go opposite directions.

Hence,

let v be peter's speed

27 = 6x3 + vx3

27 = 18 + 3v

27-18 = 3v

9 = 3v

v = 9/3

v = 3 km/h

Ostrovityanka [42]2 years ago
4 0

Answer: 3km/h

Step-by-step explanation:

Johns average speed was 6km/h, so in 3 hours he traveled 18 km.  27-18=9, so Peter ran 9 km in 3 hours.  9/3 = 3, so his average speed was 3km/h

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3 years ago
How would the sum of cubes formula be used to factor x3y3 + 343? Explain the process. Do not write the factorization.
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Answer:

Given : Expression -x^3y^3+343

To find : How would the sum of cubes formula be used to factor given expression? Explain the process. Do not write the factorization.

Solution :

The formula of sum of cubes is,

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On comparison with the formula,

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\left(xy\right)^3+7^3=(xy+7)((xy)^2-7xy+49)            

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3 years ago
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